Answer:
Explanation:
Using the Condition That Initial Angular Velocity is equal to final angular velocity
total angular momentum is equal to angular momentum of the person + angular Momentum of the Platform
Note L= I ×ω
Final Angular momentum of the person is equal to the final angular momentum of the platform
Final Moment of Inertia of the person I_{per.f} =
=70×(2.7)²=510.3Kgm2
Initial Angular Momentum L_{i} = Final Angular Momentum L_{f}
I_{plat.i} ×ω_{plat.i} + I_{per.i} ×ω_{per.i} = I_{plat.f} ×ω_{plat.f} + I_{per.f} ×ω_{per.f}
890(0.85) + 0 =890(ω_{plat.f}) +510.3(ω_{plat.f})
756.5 = 1400.3 (ω_{plat.f})
(ω_{plat.f}) =0.54rad/s
The law of conservation of mass<span> states that </span>mass<span> in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the </span>law of conservation of mass<span>, the </span>mass<span> of the products in a chemical reaction must equal the </span>mass<span> of the reactants.
</span>
Every chemical equation<span> adheres to the </span>law of conservation of mass<span>, which states that </span>matter<span> cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical </span>equation.
NH4OH is the answer. Hope this helps you.
Answer:
1.17 m
Explanation:
From the question,
s₁ = vt₁/2................ Equation 1
Where s₁ = distance of the reflecting object for the first echo, v = speed of the sound in air, t₁ = time to dectect the first echo.
Given: v = 343 m/s, t = 0.0115 s
Substitute into equation 1
s₁ = (343×0.0115)/2
s₁ = 1.97 m.
Similarly,
s₂ = vt₂/2.................. Equation 2
Where s₂ = distance of the reflecting object for the second echo, t₂ = Time taken to detect the second echo
Given: v = 343 m/s, t₂ = 0.0183 s
Substitute into equation 2
s₂ = (343×0.0183)/2
s₂ = 3.14 m
The distance moved by the reflecting object from s₁ to s₂ = s₂-s₁
s₂-s₁ = (3.14-1.97) m = 1.17 m
Answer:
680 J
Explanation:
Mechanical energy = potential energy + kinetic energy
ME = PE + KE
ME = mgh + ½ mv²
ME = (77.1 kg) (9.8 m/s²) (0.90 m) + ½ (77.1 kg) (0 m/s)²
ME = 680 J
