Answer:A) 19.8 seconds
B) 467.5 metres
Explanation: 100km/hr = 27.78m/s
So, it covers 27.78 metres in one second
Take the time it would cover 550m as x
Therefore 27.78m = 1second
550m = x
Cross multiplying
27.78x = 550m
Divide both sides by the coefficient of x
x = 550÷27.78
x = 19.8seconds
B) distance = speed × time
Speed = 85km/hr = 23.61m/s
Time = 19.8seconds
Therefore,
Distance = 23.61 × 19.8
Distance = 467.5m
When light crosses the boundary between layers with different densities, the light is refracted. (A).
Circularity system........…….......
Answer:
An <u>applied force</u> is a force that is applied to an object by a person or another object. If a person is pushing a desk across the room, then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person.
A <u>friction force</u> is the force exerted by a surface as an object moves across it or makes an effort to move across it. There are at least two types of friction force - sliding and static friction. Though it is not always the case, the friction force often opposes the motion of an object. For example, if a book slides across the surface of a desk, then the desk exerts a friction force in the opposite direction of its motion. Friction results from the two surfaces being pressed together closely, causing intermolecular attractive forces between molecules of different surfaces. As such, friction depends upon the nature of the two surfaces and upon the degree to which they are pressed together. The maximum amount of friction force that a surface can exert upon an object can be calculated using the formula below:
= µ •
Question
What was the initial momentum of the bullet before collision?
Answer:
10 Kg.m/s
Explanation:
Momentum is a product of velocity of an object in m/s and its mass in kgs hence numerically expressed as p=mv where p is momentum, v is velocity and m is mass. Substituting m for 0.2 kg and v for 50 m/s then p=0.2*50=10 kg.m/s