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pshichka [43]
3 years ago
11

Describe how neutrons were discovered

Chemistry
1 answer:
xxMikexx [17]3 years ago
6 0
Originally scientists believed in the plum pudding model of the atom (sphere of positive charge surrounded by smaller spheres of negative charge) then Rutherford did his scattering experiment (he shot alpha particles at a piece of gold foil some particles passed straight through the empty space of the atom, some were slightly deflected as they were closer to the atom's nucleus and some were completely reflected because they were headed in the path of the atom's nucleus
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F - O - S - Mg - Ba

Explanation:

as you move left to right on the periodic table the number of electrons increase.

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Prepare a list of objects around you that are electroplated​
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Hello! Some household items that are electroplated include kitchenware, such as metal pots and pans, door handles, mobile phones, and coins. An electroplated object is coated by electrolytic deposition with chromium, silver, or another metal.

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2 years ago
2. The Density of Water is 1.0000g/cm3. Based on this property of water,
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if the object sank then that object has a greater density then water. if the object floated then its density is lower then water.

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3 years ago
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7 0
3 years ago
Read 2 more answers
A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

3 0
3 years ago
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