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stiks02 [169]
3 years ago
6

Always refill your gas tank well before

Engineering
1 answer:
Scorpion4ik [409]3 years ago
8 0
I believe it’s c because you don’t want your gas to run real low, so I think it’s best to do it when your fuel.
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function summedValue = SummationWithLoop(userNum) % Summation of all values from 1 to userNum summedValue = 0; i = 1; % Write a
Alexeev081 [22]

Answer:

function summedValue = SummationWithLoop(userNum)

% Summation of all values from 1 to userNum

  summedValue = 0;

  i = 0;

  % use a while loop that assigns summedValue with the

  % sum of all values from 1 to userNum

  while(i <= userNum)

      summedValue = summedValue + i;

      i = i + 1;

  end

end

8 0
3 years ago
6.03 Discussion: Then &amp; Now - Safety
34kurt

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

6 0
3 years ago
Fluorescent troffers are a type of _ lighting fixture
creativ13 [48]
The answer would be letter A
8 0
3 years ago
If the rotational speed of a pump motor is reduced by 35%, what is the effect on the pump performance in terms of capacity, head
FinnZ [79.3K]

Answer:

- the capacity of the pump reduces by 35%.

- the head gets reduced by 57%.

the power consumption by the pump is reduced by 72%

Explanation:

the pump capacity is related to the speed as speed is reduces by 35%

so new speed is (100 - 35) = 65% of orginal speed

speed Q ∝ N ⇒ Q1/Q2 = N1/N2

Q2 = (N2/N1)Q1    

Q2 = (65/100)Q1

which means that the capacity of the pump is also reduces by 35%.

the head in a pump is related by

H ∝ N² ⇒ H1/H2 = N1²/N2²

H2 = (N2N1)²H1

H2 = (65/100)²H1 = 0.4225H1

so the head gets reduced by 1 - 0.4225 = 0.5775 which is 57%.

Now The power requirement of a pump is related as

P ∝ N³ ⇒ P1/P2 = N1³/N2³

P2 = (N2/N1)³P1

H2 = (65/100)²P1 = 0.274P1

So the reduction in power is 1 - 0.274 = 0.725 which is 72%

Therefore for a reduction of 35% of speed there is a reduction of 72% of the power consumption by the pump.  

8 0
3 years ago
An alternating current E(t) =120 sin(12t) has been running through a simple circuit for a long time. The circuit has an inductan
german

Answer:

Explanation:

we have given E(t)=120 sin(12t)

R=5 ohm

L=0.2 H

ω=12 ( from expression of E)

X_L=0.2\times 12=2.4 ohm

X_C=\frac{1}{\omega \times C}=\frac{1}{12\times 0.043}=1.9379\ ohm

Z=\sqrt{R^2+\left ( \omega L-\frac{1}{\omega C} \right )^2}

Z=\sqrt{5^2+\left ( \2.4-1.9379 )^2}

=5.021 ohm

so amplitude of current =  \frac{v}{z}=\frac{120}{5.021}=23.89

4 0
3 years ago
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