Question

In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 630 nm is then projected through the same slits. How far from the central bright spot will the second-order maximum of this light be located?

Answer 1

Answer:

The distance from the central bright spot is 13.73 mm.

Explanation:

Given that,

Wavelength = 520 nm

Width d= 17 mm

Distance L= 1.6 m

Order = 3

We need to calculate the distance from the central bright spot

Using formula of distance

$y=\dfrac{m\lambda L}{d}$

Put the value into the formula

$y=\dfrac{3\times520\times10^{-9}\times1.6}{17\times10^{-3}}$

$y=0.0001468=146.8\times10^{-6}\ m$

Now, the wavelength is changed to 630 nm

We  need to calculate the distance from the central bright spot with the second order of this light

$y=\dfrac{2\times630\times10^{-9}\times1.6}{146.8\times10^{-6}}$

$y=0.0137=13.73\times10^{-3}\ m$

$y=13.73\ mm$

Hence, The distance from the central bright spot is 13.73 mm.