F = ma = -kx
a = 9.81 m/s²
k = 3430 N/m
m = 70 kg
x = - ma/ k = 0.2m
The time period of the simple pendulum is 2.4 seconds.
Given the data in the question;
- Time taken to swing from leftmost point to rightmost point;
- Period of the pendulum;
<h3>What is Period?</h3>
Period is the time needed for a complete cycle of vibration to pass a given point.
Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.
Now, if it took the pendulum 
to swing from leftmost point to rightmost point, it will also take the pendulum to swing back to its original position( leftmost point )
Hence,
= time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.
Therefore, the time period of the simple pendulum is 2.4 seconds.
Learn more about Time Period: brainly.com/question/27135322
Answer:
Explanation:
When an moving electric charge passes through a uniform magnetic field
its motion becomes circular .
If m be the mass v be the velocity , q be the charge on the mass B be the magnetic field and R be the radius of circular path
force on the moving charge created by magnetic field
= B q v
Centripetal force required for circular motion
= m v² / R
For balancing
B q v = m v² / R
v = B q R / m
Time period of rotation
T = 2π R / v
= 2 π R m / B q R
= 2 π m / B q
For first particle
T₁ = 2 π m₁ / B q₁
For second particle
T₂ = 2 π m₂ / B q₂
q₁ = q₂ and 10 m₁ = m₂ ( given )
Putting the values in second equation
T₂ = 2 π 10 m₁ / B q₁
= 10 x 2 π m₁ / B q₁
= 10 T₁
Given T₁ = T
T₂ = 10 T
Answer:
the correct answer is D.) 2,4
