Consider the following equation:
C7H9 + 3 HNO3 → C7H6(NO2)3 + 3 H2O
Identify the product(s) for this reaction.
a. C7H6(NO2)3
b. H2O
c. HNO3 d. C7H9 and H2O
<u>e. C7H6(NO2)3 and H2O</u>
Answer:
8.7 mol Al
Explanation:
You have the compound Al₂Si₄O₁₀(OH)₂. Within the compound, you have atoms. You can tell how many atoms there are by looking at the subscript. You have 2 aluminum atoms, giving you 8.7 moles of aluminum.
4.35 × 2 = 8.7
It should be wind direction
Explanation:
I hope this helps. Let me know if I am wrong
Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).