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3 years ago

WHAT THE DEFINITION OD ENGINEER. No CHEAT

Computers and Technology

2 answers:

kondaur [170]3 years ago

8 0

Someone who operates a train

Harrizon [31]3 years ago

4 0

A person who designs, maintains or builds machines.

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Hey good to mett you

ella [17]

Answer:

You too?

Explanation:

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3 years ago

One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are r

Marina CMI [18]

Answer:

Number of packets ≈ 5339

Explanation:

let

X = no of packets that is not erased.

P ( each packet getting erased ) = 0.8

P ( each packet not getting erased ) = 0.2

P ( X ≥ 1000 ) = 0.99

E(x) = n * 0.2

var ( x ) = n * 0.2 * 0.8

∴ Z = X - ( n * 0.2 ) / $\sqrt{n*0.2*0.8}$ ~ N ( 0.1 )

attached below is the remaining part of the solution

note : For the value of <em>n</em> take the positive number

5 0

3 years ago

A(n) ________ is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.

melomori [17]

A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.

<h3>What is an access point?</h3>

An access point is known to be a kind of device that makes a wireless local area network, or WLAN, and it is often done in an office or big building.

Therefore, A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.

Learn more about access point from

brainly.com/question/14306861

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6 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Match each of the following steps of SDLC development to its position in the development process.

Arisa [49]

Answer:

Step One - problem/opportunity identification (V)

Step Two - Analysis (III)

Step Three - Design (II)

Step Four - Development (I)

Step Five - Testing and Installation (IV)

Explanation:

In the field of software development, or systems engineering, SDLC which refers to software development cycle refers to a systematic way of building software applications, it shows unique stages with the outcome of each stage dependent on the previous, step has a unique task which range from the planning, analysis, development, testing and installation of the information system.

5 0

3 years ago