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pantera1 [17]
2 years ago
11

PLEASE HELP

Chemistry
2 answers:
saveliy_v [14]2 years ago
8 0

If it's not preservation then it's it's reservation.

victus00 [196]2 years ago
7 0

Answer:

A restoration

Explanation:

the action of returning something to a former owner, place, or condition.

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What is the percent of Cr in Cr2O3
IgorLugansk [536]
The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
           Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
     2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
          Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
                   = \frac{103.98}{151.98} × 100
                   
                   = 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
5 0
3 years ago
Read 2 more answers
Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0
3 years ago
What is cell theory and why is it important
IceJOKER [234]
Cells are the basic unit of structure in all organisms and also the basic unit of reproduction.

What is the this (^ that up there) a description of?
5 0
3 years ago
A solution is formed by mixing 0.400 mol NaOH
leonid [27]

Answer:

The correct answer is m= mol solute kg soivent

Explanation:

Molality is a measure of concentration, which indicates the moles of solute (in this case sodium hydroxide) in 1kg of solvent .

In this case:

0,800 kg water-----0,400 mol NaOH

1 ,000 kg water ---x=(1 ,000 kg water x 0,400 mol NaOH)/0,800 kg water

x=0,5 mol NaOH---> <em>The solution is 0,5 molal (0,5 m)</em>

6 0
3 years ago
How do both plants and animals fight pathogens. A.both have a protective outer layer B.both have an antigen-antibody response C.
ira [324]
<span>Both plants and animals fight pathogens is because both have an ant. </span><span>The answer is B. 

P</span>athogens is <span>a bacterium, virus, or other microorganism that can cause disease.

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3 0
4 years ago
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