All categories

2 years ago

PLEASE HELP

Chemistry

2 answers:

saveliy_v [14]2 years ago

8 0

If it's not preservation then it's it's reservation.

victus00 [196]2 years ago

7 0

Answer:

A restoration

Explanation:

the action of returning something to a former owner, place, or condition.

You might be interested in

What is the percent of Cr in Cr2O3

IgorLugansk [536]

The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
= $\frac{103.98}{151.98}$ × 100

= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.

5 0

3 years ago

Read 2 more answers

Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin

STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of $KI$ and $AgNO_3$ .

$\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}$

Molar mass of KI = 166 g/mole

$\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole$

and,

$\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole$

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

$KI+AgNO_3\rightarrow KNO_3+AgI$

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of $AgNO_3$

So, 0.0178 mole of KI react with 0.0178 mole of $AgNO_3$

From this we conclude that, $AgNO_3$ is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgI$

From the reaction, we conclude that

As, 1 mole of $KI$ react to give 1 mole of $AgI$

So, 0.0178 moles of $KI$ react to give 0.0178 moles of $AgI$

Thus,

Moles of AgI = Moles of $I^-$ anion = Moles of $Ag^+$ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

$\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}$

$\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M$

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0

3 years ago

What is cell theory and why is it important

IceJOKER [234]

Cells are the basic unit of structure in all organisms and also the basic unit of reproduction.

What is the this (^ that up there) a description of?

5 0

3 years ago

A solution is formed by mixing 0.400 mol NaOH

leonid [27]

Answer:

The correct answer is m= mol solute kg soivent

Explanation:

Molality is a measure of concentration, which indicates the moles of solute (in this case sodium hydroxide) in 1kg of solvent .

In this case:

0,800 kg water-----0,400 mol NaOH

1 ,000 kg water ---x=(1 ,000 kg water x 0,400 mol NaOH)/0,800 kg water

x=0,5 mol NaOH---> The solution is 0,5 molal (0,5 m)

6 0

3 years ago

How do both plants and animals fight pathogens. A.both have a protective outer layer B.both have an antigen-antibody response C.

ira [324]

Both plants and animals fight pathogens is because both have an ant. The answer is B.

Pathogens is a bacterium, virus, or other microorganism that can cause disease.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

3 0

4 years ago

Read 2 more answers