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motikmotik
3 years ago
8

. Explain what happens to each ball after the collision. Why do you think this

Physics
2 answers:
guajiro [1.7K]3 years ago
5 0
This represents Newtons 3rd law

FrozenT [24]3 years ago
3 0
They hit each other.This is the 3rd law I think

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Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un
Naya [18.7K]

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

Equating both we get :

C_{liquid}=1.258 \ J/g^0C.

7 0
3 years ago
A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat c
sesenic [268]

Answer: Induced emf is given by:

ε= Bvl

On putting the values we get

=5×10

−5

×1.50×2

=0.15mV

Explanation:

Hope these helped have a wonderful Christmas break ❄️

7 0
3 years ago
A heavy copper ball of mass 2 kg is dropped from a fiftieth-floor apartment window. Another one with mass 1 kg is dropped immedi
STALIN [3.7K]

Answer:

C

Explanation:

Because everything on Earth falls at the same speed, the masses of the balls do not matter. Since the acceleration due to gravity is constant, their speeds will both be increasing at the same rate, and therefore the difference in speeds would remain constant until they hit the ground. Hope this helps!

5 0
3 years ago
By method of dimension show that the following equation are homogenous.
il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

i)

Given equation is:

H = \frac{u^2Sin^2\phi}{2g}

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]

<u>[L] = [L]</u>

Hence, the equation is proven to be homogenous.

ii)

F = \frac{Gm_1m_2}{r^2}\\\\

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\

<u>[MLT⁻²] = [MLT⁻²]</u>

Hence, the equation is proven to be homogenous.

8 0
3 years ago
Which picture correctly shows the path of the reflected light rays given an object outside the focal point?Select one:a. Ab. Bc.
nignag [31]

We will have that the graph that describes the scenario is given by graph B.

6 0
1 year ago
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