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3 years ago

What is an intraplate quake? What causes them?

1 answer:

8 0

intraplate earthquake occurs in the interior of a tectonic plate, basically its a lower version of an earth quake but just less damage. The cause of them is the two tectonic plate hitting each other or i should say sliding togather.

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Solved, can someone check it over!

kakasveta [241]

Answer:

its good no need to change anything :))

4 0

3 years ago

The graph in the accompanying figure (Figure 1) shows the magnitude of the force exerted by a given spring as a function of the

serious [3.7K]

The elastic potential energy stored in the stretched spring is 1 J.

<h3>What is Hooke's law?</h3>

Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.

Given that;

Force on the spring = 350 Newton

Distance stretched = 7 centimeters or 0.07 m

Hence;

F = ke

k = F/e = 350 Newton/0.07 m = 5000 N/m

Work done in stretching a spring = 1/2ke^2

= 0.5 × 5000 × (2 × 10^-2)^2 =1 J

Learn more about elastic potential energy: brainly.com/question/156316

4 0

2 years ago

When the velocity of an object is doubled, by what factor is its momentum changed? By what factor is its kinetic energy changed?

anzhelika [568]

Answer:

Kinetic energy would increase by a factor of 4 where as momentum would increase by a factor of 2.

Explanation:

Kinetic Energy is given by 0.5*mass*velocity^2. Kinetic Energy is proportional to Velocity^2.

Momentum is given by mass*velocity. Momentum is proportional to Velocity.

If the velocity of an object is doubled, Kinetic energy would increase by a factor of 2^2 i.e 4 times. Momentum would increase by a factor of 2.

4 0

3 years ago

Jane and John Doppler effect

UkoKoshka [18]

Answer:

To summarize, Jane's star has a red light and is traveling towards the Earth while John's star has a blue light and is traveling away from the Earth. This is a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

4 0

3 years ago

The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

Mama L [17]

A) Time needed: 6.24 s

B) Time needed: 2.86 s

Explanation:

In this part, we are told that the power if the engine is constant. The power of the engine is given by

$P=\frac{W}{t}$

where

W is the work done

t is the time

This means that the power of the engine is proportional to the work done, and therefore, to the kinetic energy of the car:

$P=\frac{\frac{1}{2}mv^2}{t}=const.$

where m is the mass of the car and v its velocity.

SInce power is constant, we can write:

$\frac{\frac{1}{2}mv_1^2}{t_1^2}=\frac{\frac{1}{2}mv_2^2}{t_2}$

where:

$t_1=1.40 s$ is the time the car needs to accelerates to $v_1=28.0 mph$

$t_2$ is the time the car needs to accelerate to $v_2=57.0 mph$

Therefore, solving for $t_2$ ,

$t_2 = \frac{v^2}{u^2}t_1=\frac{57^2}{28^2}(1.40)=6.24 s$

First of all, we have to calculate the acceleration of the car. We can do it using the following equation:

$a=\frac{v-u}{t}$

where:

u = 0 is the initial velocity

$v=28.0 mph \cdot \frac{1609 m/mi}{3600 s/h}=12.5 m/s$ is the final velocity

t = 1.40 s is the time elapsed

Substituting, we find the acceleration:

$a=\frac{12.5-0}{1.40}=8.9 m/s^2$

In this part, we are told that the force exerted by the engine is constant: according to Newton's second law, acceleration is proportional to the force,

$F=ma$