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Zepler [3.9K]
3 years ago
8

Amplitude and energy are inversely related, meaning that a high-energy wave has low amplitude and a low-energy wave has high amp

litude.
True
False
Physics
1 answer:
Elodia [21]3 years ago
8 0
According to the physical fact that a<span>mplitude and energy have proportional values, this statement is definitely FALSE. Pay attention on the words ''</span><span> inversely related'', that will be the main point which will make it absolutely clear. Hope you will find this answer helpful! Regards.</span>
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Someone help find centripetal acceleration plus centripetal force!
Arte-miy333 [17]

Answer:Centripetal force that acts an object keep it along a moving circular path.

Explanation:Centripetal force along a path circular of radius(r) with velocity(V) acceleration the center of the path.

a=v/r

object will along moving continue a straight path unless by the external force.External force is the centripetal force.

Centripetal force is to moving in horizontal circle,Centripetal force is not a fundamental force.Gravitational force satellite and orbit of centripetal force.

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4 years ago
An element is ____
Likurg_2 [28]

An element is C. A substance with only one type of Atom

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What factors cause a rock to become a sedimentary rock
erica [24]

Answer:

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Explanation:

3 0
3 years ago
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Air at 1.3 bar, 423 K and a velocity of 40 m/s enters a nozzle operating at steady state and expands adiabatically to the exit,
bixtya [17]

Answer:

a) T₂ = 376.905 K

b) \eta_n = 95.4%

Explanation:

Given:

Initial pressure, P₁ = 1.3 bar

Initial temperature, T₁ = 423 K

Initial velocity of air, v₁ = 40 m/s

Exit pressure, P₂ = 0.85 bar

Exit velocity of the air, v₂ = 307 m/s

gas constant for air, k = 1.4

also,

the specific heat for the air, Cp = 1.005 KJ/kg.K =1.005 × 10³ J/kg.K   (standard)

a) applying the energy rate balance, we have

h_1+\frac{v_1^2}{2}=h_2+\frac{v_2^2}{2}

where, h is the enthalpy

on rearranging we get

\frac{v_2^2-v_1^2}{2}=h_1-h_2

also

h = Cp × T

thus,

\frac{v_2^2-v_1^2}{2}=C_p(T_1-T_2)

on substituting the values, we get

\frac{307^2-40^2}{2}=1.005\times 10^3(423-T_2)

or

T₂ = 376.905 K

b) The  isentropic nozzle efficiency is given as:

\eta_n=\frac{V_2^2/2}{V_1^2/2}=\frac{Actual\ expansion}{Ideal\ Expansion}

for an isentropic process,we have the isentropic relation as:

\frac{T_{2s}}{T_1}=(\frac{P_2}{P_1})^{\frac{k-1}{k}}

on substituting the values and solving, we get

T_{2s} = 374.65 K

by applying the energy equation, we get the ideal exit velocity as:

V_{2s}=\sqrt{2C_p(T_2-T_1)+V_1^2}

on substituting the values, we get

V_{2s}=\sqrt{2\times1.005\times10^3(423-374.65)+40^2}

or

V_{2s}=314.29\ m/s

thus,

substituting in the formula for efficiency, we get

\eta_n=\frac{307^2/2}{314.29^2/2}

or

\eta_n=0.954 = 95.4%

5 0
3 years ago
A submarine is built to dive to a depth of 90 m where the pressure in the water is about 1 MPa. The engineers want to build a wi
Agata [3.3K]

Answer:

<em>The largest surface area window that can be used is</em> A=0.01\ m^2

Explanation:

<u>Pressure</u>

The pressure is defined as force per unit area. The SI unit for pressure is the Pascal (Pa), defined as Newton per square meter.

If a force F acts on a surface area A, the pressure is calculated as:

\displaystyle P=\frac{F}{A}

The pressure at a depth of 90 m is P=1 Mpa= 1,000,000 Pa and the submarine's window can only take a force of F=10 kN=10,000 N.

We need to calculate the largest surface area of the window. We can solve the equation for A:

\displaystyle A=\frac{F}{P}

Substituting:

\displaystyle A=\frac{10,000}{1,000,000}

A=0.01\ m^2

The largest surface area window that can be used is \mathbf{A=0.01\ m^2}

4 0
3 years ago
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