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3 years ago

Which of the following is necessary to do a complete stoichiometric calculation? A) Add the nuclear masses of the products.

Chemistry

1 answer:

Katena32 [7]3 years ago

5 0

Answer:

Option (C). Write the complete balanced chemical equation.

Explanation:

Writing a balanced chemical equation is the key to arriving at the correct stoichiometric calculations because it gives a fore knowledge of the correct amount of reactants needed to generate a predicted products for a given reaction

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Look at the diagram below.

Irina-Kira [14]

Answer:

if charge of ion is positive then it will loose electron

if charge of ion is negative it will gain electron

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2 years ago

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15. The starting diol for this molecule is

victus00 [196]

<h2>Answer with explanation </h2>

<h3><em>The starting diol for this molecule is :-</em></h3><h3><em>The starting diol for this molecule is :-D) ethan-1,2-diol.</em></h3>

<em>Hope </em><em>my </em><em>answer </em><em>is</em><em> helpful</em><em> to</em><em> you</em><em> </em><em>☺️</em>

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3 years ago

Students in Ms. Winters' class were interested in testing the antibacterial strength of hand soap versus hand sanitizer. The stu

KatRina [158]

My answer is a please tell me if I helped

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2 years ago

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If you hit the surface of Iron with a photon of energy and find that the ejected electron has a wavelength of .75 nm, what is th

lubasha [3.4K]

Answer:

The wavelength of the incoming photon is 172.8 nm

Explanation:

The wavelength of the incoming photon can be calculated with the photoelectric equation:

$KE = h\frac{c}{\lambda_{p}} - \phi$ (1)

Where:

KE: is the kinetic energy of the electron

h: is Planck's constant = 6.62x10⁻³⁴ J.s

c: is the speed of light = 3.00x10⁸ m/s

$\lambda_{p}$ : is the wavelength of the photon =?

Φ: is the work function of the surface (Iron) = 4.5 eV

The kinetic energy of the electron is given by:

$KE = \frac{p^{2}}{2m} = \frac{(\frac{h}{\lambda_{e}})^{2}}{2m}$ (2)

Where:

p: is the linear momentum = h/λ

m: is the electron's mass = 9.1x10⁻³¹ kg

$\lambda_{e}$ : is the wavelength of the electron = 0.75 nm = 0.75x10⁻⁹ m

Hence, the wavelength of the photon is:

$\frac{(\frac{h}{\lambda_{e}})^{2}}{2m} = h\frac{c}{\lambda_{p}} - \phi$

$\lambda_{p} = \frac{hc}{\frac{h^{2}}{2m\lambda_{e}^{2}} + \phi} = \frac{6.62 \cdot 10^{-34} J.s*3.00\cdot 10^{8} m/s}{\frac{(6.62 \cdot 10^{-34} J.s)^{2}}{2*9.1 \cdot 10^{-31} kg*(0.75 \cdot 10^{-9} m)^{2}} + 4.5 eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}} = 1.728 \cdot 10^{-7} m = 172.8 nm$

Therefore, the wavelength of the incoming photon is 172.8 nm.

I hope it helps you!

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3 years ago

4. A,B,AB or O. <br><br><br> 5. A,B,AB or O<br><br><br> 6. A,B,AB or O

Gemiola [76]

Answer:

4. Blood types B and O

5. Blood types B and O

6. Blood types A, B AB, and O

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2 years ago