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Compared to the bedrock layers above and below the rock ledge shown at the waterfall, the characteristic that is primarily respo

lubasha [3.4K]

<span>The best and most correct answer among the choices provided by the question is the first choice. The characteristic that is primarily responsible for the existence of the rock ledge is its greater resistance to weathering. I hope my answer has come to your help. God bless and have a nice day ahead!</span>

5 0

3 years ago

Read 2 more answers

Give the product expected when the following alcohol reacts with pyridinium chlorochromate (PCC). (Assume that PCC is present in

stiks02 [169]

Answer:

Explanation:

From the information given, we are to show the product of the reaction between the alcohol (stick formula) with pyridinium chlorochromate. The reaction starts with the nucleophilic addition of Cr with oxygen molecule on the alcohol. Then, deprotonation of oxygen occurs, this process is followed by the removal of hydrogen ion to yield the final product. The reaction mechanism can be seen from the attached image below.

4 0

3 years ago

Pentaborane-9,

frozen [14]

Given question is incomplete. The complete question is as follows.

Pentaborane ( $B_{5}H_{9}$ ) is a colorless highly reactive liquid that will burst into flames when exposed to oxygen.the reaction is:

$2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)$

Calculate the kilojoules of heat released per gram of the compound reacted with oxygen.the standard enthalpy of formation $B_{5}H_{9}(l)$ , $B_{2}O_{3}(s)$ , and $H_{2}O(l)$ are 73.2, -1271.94, and -285.83 kJ/mol, respectively.

Explanation:

As the given reaction is as follows.

$2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)$

Therefore, formula to calculate the heat energy released is as follows.

$\Delta H = \sum H_{products} - \Delta H_{reactants}$

Hence, putting the given values into the above formula is as follows.

$\Delta H = \sum H_{products} - \Delta H_{reactants}$

= $5 \times (-1271.94 kJ/mol) + 9 \times (-285.83 kJ/mol) - 2 \times (73.2 kJ/mol) - 12(0)$

= -9078.59 kJ/mol

Since, 2 moles of Pentaborane reacts with oxygen. Therefore, heat of reaction for 2 moles of Pentaborane is calculated as follows.

$\frac{\Delta H}{2 \times \text{molar mass of pentaborane}}$

$\frac{-9078.59 kJ/mol}{2 \times 63.12 g/mol}$

= -71.915 kJ/g

Thus, we can conclude that heat released per gram of the compound reacted with oxygen is 71.915 kJ/g.

8 0

3 years ago

*<br> The prevailing weather patterns of a region

elena-s [515]

Answer:

noun. the composite or generally prevailing weather conditions of a region, as temperature, air pressure, humidity, precipitation, sunshine, cloudiness, and winds, throughout the year, averaged over a series of years. a region or area characterized by a given climate: to move to a warm climate.

Explanation:

8 0

3 years ago

Describe one physical and 1 Chemical way that the salt could be separated from the water

SOVA2 [1]

Answer:

if it dont dissolve

Explanation:

8 0

3 years ago