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Sophie [7]
2 years ago
11

if you throw a ball straight up into the air at a velocity of 15 m/s you want to know how high above your hand the ball will be

at exactly 2.5 sec after you released it ​
Physics
1 answer:
xxMikexx [17]2 years ago
4 0

Answer:

 Assuming that gravity has not caused the ball to start falling then after 2.5 seconds the ball will be 37.5 meters in the air

Explanation:

The ball travels 15 meters every second so for 2 seconds we would multiply 15*2=30. We have 2.5 seconds so to calculate the time traveled in half a second we would divide 15/2=7.5

Then we add 30+7.5= 37.5 meters

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Derive the expression for the equivalent resistance of three resistors in[1] paraleli [2] series
sergeinik [125]
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.

When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
8 0
3 years ago
A 30-gram bullet is fired and a 50-gram bullet is dropped simultaneously from the same height. Which will hit the ground first?
Marina86 [1]

Answer: the 30gram will hit the ground first

Explanation:the 30gram bullet will hit the ground first because it is fired

4 0
3 years ago
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What if an object traveled from position -6 m to -1 m, what is the distance traveled?
Oxana [17]
The object traveled +5 m
4 0
3 years ago
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Match the following:
joja [24]

Explanation:

1. study of conversion of heat to mechanics → thermodynamics

A branch of physical science which deals with heat and other forms of energy.

2. The Law of Conservation of Energy  → first Law of Thermodynamics

Energy cannot be created nor be destroyed. According to first law of thermodynamics total energy of the system is always constant.

3. Result of applied energy  → work

Work is the way of system to release its energy.

4. Principle that states that in any energy transformation some energy is dissipated as heat  → Second Law of Thermodynamics

5. energy of motion  → kinetic energy

Kinetic energy is defined as energy possessed by the body due to its motion.

6. work/displacement  → force

Work is product of force and displacement.

Work=Force \times displacement

Force=\frac{Work}{displacement}

7. power · time  → energy

Power is defined energy per unit time.

Power=\frac{Energy}{Time}

Energy=Power\times Time

8. Device that transforms heat energy into mechanical energy →  heat engine

heat engine is a device which converts the heat energy which is released due to combustion of fuel into a useful work that is mechanical energy.

9 . Energy due to position  → potential energy

Potential energy is defined as energy possessed by the body due to its position.

10. efficiency of a heat engine unit of heat  → calorie

11. Measure of molecular motion  → Temperature

Kinetic energy is directly proportional to temperature.

Greater the motion more will be the kinetic energy and with more will be the temperature.

12. Heat given off by a liquid with no change in temperature  → latent heat of fusion

Latent heat of fusion is defined as heat released by 1 mole of substance when it under goes phase change that is from solid to liquid.

13. Motion within solids  → vibrational motion

Vibrational motion is the motion in which particle oscillates from its mean position.

14. Phase of matter on the sun → plasma

Plasma is hot ionized gas with equal number of positive and negative ions. Due to high temperature of sun most the gas are in the plasma state.

8 0
3 years ago
A metallic wire has a diameter of 4.12mm. When the current in the wire is 8.00A, the drift velocity is 5.40×10−5m/s.What is the
podryga [215]

Answer:

6.9\times 10^{28}m^{-3}

Explanation:

We are given that

Diameter of wire=d=4.12 mm

Radius of wire=rr=\frac{d}{2}=\frac{4.12}{2}=2.06mm=2.06\times 10^{-3} m

1mm=10^{-3} m

Current=I=8 A

Drift velocity=v_d=5.4\times 10^{-5} m/s

We have to find the density of free electrons in the metal

We know that

Density of electron=n=\frac{I}{v_deA}

Using the formula

Density of free electrons=\frac{8}{5.4\times 10^{-5}\times 1.6\times 10^{-19}\times 3.14\times (2.06\times 10^{-3})^2}

By using Area of wire=\pi r^2

\pi=3.14\\e=1.6\times 10^{-19} C

Density of free electrons=6.9\times 10^{28}m^{-3}

3 0
3 years ago
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