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valkas [14]
3 years ago
14

A 6.0-ω and a 12-ω resistor are connected in parallel across an ideal 36-v battery. What power is dissipated by the 6.0-ω res

istor?
Physics
1 answer:
Elena L [17]3 years ago
8 0

Answer:

P = 216 Watts  

Explanation:

Given that,

Resistance 1, R_1=6\ \Omega

Resistance 2, R_2=12\ \Omega

Voltage, V = 36 V

We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.      

Firstly, lets find current of the 6 ohms resistor such that,

V = IR

I=\dfrac{V}{R}\\\\I=\dfrac{36}{6}\\\\I=6\ A

The power dissipated by 6 ohms resistor is given by :

P=I^2R

P=6^2\times 6\\\\P=216\ W

So, the power dissipated across 6 ohm resistor is 126 watts.

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