The gas would diffuse as much as it could
We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:
0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced
To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,
0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL
2 moles of NaOH dissolved in 1 litre of solution is the solution with more concentration.
Answer: Option A
<u>Explanation:</u>
Concentration of solution is the measure of the amount of solute dissolved in the solvent of the solution. So this is measured using the molarity of the solution. Molarity is determined as the number of moles of the solute present in the given amount of solvent.
In this present case, the option A gives the molarity of 2 M as
But the second option, mass of NaOH is given. So we have to determine the molarity. First we have to find the molar mass of NaOH. We know that 1 mole of NaOH will contain 40 g/mole.
1 g of NaOH = 40 g of NaOH
1 g of NaOH = 1/40 moles
So 2 g of NaOH will contain which is equal to 0.05 moles of NaOH.
Thus, the molarity of 2 g of NaOH will be
Molarity = =0.05 M
Thus, the option A is having higher concentration as the molarity is more for 2 moles of NaOH dissolved in 1 l of solution.
Answer:
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Explanation:
This is from Liv and Maddie