The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
<h3>
Maximum speed of the face</h3>
v = fλ
where;
- f is frequency of the wave
- λ is the wavelength
<h3>Angular speed of the wave</h3>
ω = 2πf
v(max) = ωA
v(max) = 2πfA
where;
- A is amplitude of the wave
v(max) = 2π(215)(50 x 10⁻⁹ m)
v(max) = 6.75 x 10⁻⁵ m/s
Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
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Answer:
work accomplished = 300*30
= 9,000 J
applied work = 9,000 + 2,000 = 11,000 Joules
efficiency = 100 * work accomplished/work applied
= (9/11)100 = 81.8 %
force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage
The emf induced in the coil is -5.65 V
<h3>Induced emf in coil</h3>
The induced emf in the coil is given by ε = -NΔΦ/Δt where
- ΔΦ = change in magnetic flux Φ₂ - Φ₁ where
- Φ₁ = initial magnetic flux = -58 Wb and
- Φ₂ = final magnetic flux = 38 Wb and and
- Δt = change in time = t₂ - t₁ where
- t₁ = initial time = 0 s and
- t₂ = final time = 34 sand
- N = number of loops of coil = 2
Since ε = -NΔΦ/Δt
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
Substituting the values of the variables into the equation, we have
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)
ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)
ε = -2(96 Wb)/34 s
ε = -192 Wb/34 s
ε = -5.65 Wb/s
ε = -5.65 V
So, the emf induced in the coil is -5.65 V
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