Answer:
S=720m anf vf=12m/s
Explanation:
acceleration=a=0.1m/s²
time taken=t=2minutes=2×60=120seconds
vi=0m/s
vf=?
distance covered=S=?
by using second equation of motion
S=vit+1/2at²
S=0m/s×120seconds+1/2(0.1m/s²)(120s)²
S=0m/s+1/2×1440m
S=720m
and now we have to find the vf
vf=vi+at
vf=0m/s+(0.1m/s)(120s)
vf=12m/s
i hope it will help you
Answer:
E means energy
M= Mass
C=speed of light squared (the exponent means squared)
From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
V₃ = 5130 m/s (in iron)
Distance traveled is
d = 100 km = 10⁵ m
Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s
Time required to travel in iron is
t₂ = d/V₂ = 10⁵/5130 = 19.49 s
The difference in time is
302.12 - 19.49 = 282.63 s
Answer: 283 s (nearest second)
Answer:
Explanation:
14 lb force is required to stretch the spring by 4 inch distance
So we have
stretch in the spring is given as
now we will have
Now we need to find the work to stretch it by x = 10 in = 0.254 m
so we have
