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Lyrx [107]
3 years ago
8

What time period is jellyfish first appear

Physics
1 answer:
const2013 [10]3 years ago
7 0

According to scientists, the first fossil of a jellyfish first appeared approximately 500 million years ago. Or to be more exact, the Cambrian Period.

Hope I could help! :)

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When not in a vacuum, what force causes objects in freefall to fall at different speeds??
Deffense [45]
Hi,

My best answer would be Gravity. Is it a multiple choice question? Or is it an essay question. 
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4 years ago
Which image is observe by seeing a distant thing using magnifying glass?
lesya692 [45]

Answer:

1/f = 1/o + 1 /i       thin lens equation

1 / i = 1/f - 1/o = (o - f) / (o f)    rearranging

or i = o f / (o - f)   for the image distance

This image will be positive (real) with values given

m = -i / o      magnification

m = - f / (o - f)      shows m is negative and the image inverted

Also, since o here is large m will be small and the image is small

I think they mean A as the right answer

Different texts use different terms but here i is image distance and o the object distance

7 0
3 years ago
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Which of these refers to tempo?
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The choice that would best describe the word "tempo" would be letter A which states that it is "a pace of music or speed of beats per minute." In addition, a tempo is an important characteristic of music because it is the one who carries the emotions and feelings of the composer towards the music he/she makes. 
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3 years ago
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At a certain temperature, the speed of sound in the air is 330 meters per second. Which of the following expressions would conve
Lapatulllka [165]

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It would 110

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It is only because of a división leading you into a

3 0
3 years ago
Three identical resistors are connected in parallel. The equivalent resistance increases by 630 when one resistor is removed and
strojnjashka [21]

Answer:

each resistor is 540 Ω

Explanation:

Let's assign the letter R to the resistance of the three resistors involved in this problem. So, to start with, the three resistors are placed in parallel, which results in an equivalent resistance R_e defined by the formula:

\frac{1}{R_e}=\frac{1}{R} } +\frac{1}{R} } +\frac{1}{R} \\\frac{1}{R_e}=\frac{3}{R} \\R_e=\frac{R}{3}

Therefore, R/3 is the equivalent resistance of the initial circuit.

In the second circuit, two of the resistors are in parallel, so they are equivalent to:

\frac{1}{R'_e}=\frac{1}{R} +\frac{1}{R}\\\frac{1}{R'_e}=\frac{2}{R} \\R'_e=\frac{R}{2} \\

and when this is combined with the third resistor in series, the equivalent resistance (R''_e) of this new circuit becomes the addition of the above calculated resistance plus the resistor R (because these are connected in series):

R''_e=R'_e+R\\R''_e=\frac{R}{2} +R\\R''_e=\frac{3R}{2}

The problem states that the difference between the equivalent resistances in both circuits is given by:

R''_e=R_e+630 \,\Omega

so, we can replace our found values for the equivalent resistors (which are both in terms of R) and solve for R in this last equation:

\frac{3R}{2} =\frac{R}{3} +630\,\Omega\\\frac{3R}{2} -\frac{R}{3} = 630\,\Omega\\\frac{7R}{6} = 630\,\Omega\\\\R=\frac{6}{7} *630\,\Omega\\R=540\,\Omega

8 0
3 years ago
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