Question

A galvanic cell is powered by the following redox reaction: Br2 H2 2OH Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to decimal places.

Answer 1

Answer:

1.91 V

Explanation:

The correct cell reaction. equation is;

Br2(l) + H2(g) + 2OH-(aq) -> 2Br-(aq) + 2H2O(l)

Anode half reaction;

H2(g) + 2OH^-(aq) --------> 2H2O(l) +2e- -0.82 V

Cathode half reaction;

Br2(l) + 2e- -----> 2Br^-(aq). +1.09 V

Hence

E° cell= E°cathode - E°anode

E° cell= 1.09 - (-0.82)

E° cell= 1.91 V