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2 years ago

Below is a single strand of DNA, what is the complementary base pair for the strand?

Physics

1 answer:

GREYUIT [131]2 years ago

5 0

The complementary base pair is:
TTC, CTG, AGT, CTA.

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This type of polarization occurs when light strikes the atoms of a material.

zloy xaker [14]

Option C i.e scattering is the correct answer.

Scattering type of Polarization occurs when light strikes the atoms of a material.

Polarization is the process of transforming unpolarized light into polarized light. There are four methods of polarisation--Transmission, Refraction, Reflaction and Scattering.

4 0

3 years ago

Read 2 more answers

Please help!!

sukhopar [10]

Answer:

: WHY DIDN'T THE POD DOCK LIKE IT WAS SUPPOSED TO DO? 

ANSWER;

The force exerted by the thrusters caused the pod to change direction.

WHAT NEW THEORIES DO YOU HAVE?

ANSWER;

This pod moved differently because it was more massive.

CARRYONLEARNING:)

3 0

1 year ago

2..Read the following statements carefully and choose the correct option

Softa [21]

Answer:

statement 1 is correct

2 not sure

Explanation:

6 0

2 years ago

A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a

Luda [366]

Answer:

20 °C

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

P / T = nR / V

Since n, R, and V are constant:

P₁ / T₁ = P₂ / T₂

488.2 kPa / T = 468 kPa / 281.15 K

T = 293.29 K

T = 20.1 °C

Rounded, the temperature was 20 °C.

6 0

3 years ago

Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/m·K. The temperature of the left surface is held const

kozerog [31]

Answer:

The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

Explanation:

Thickness of the wall is L= 20cm = 0.2m

Thermal conductivity of the wall is K = 2.79 W/m·K

Temperature at the left side surface is T₁ = 50°C

Temperature of the air is T = 22°C

Convection heat transfer coefficient is h = 15 W/m2·K

Heat conduction process through wall is equal to the heat convection process so

$Q_{conduction} = Q_{convection}$

Expression for the heat conduction process is

$Q_{conduction} = \frac{K(T_1 - T)}{L}$

Expression for the heat convection process is

$Q_{convection} = h(T_2 - T)$

Substitute the expressions of conduction and convection in equation above

$Q_{conduction} = Q_{convection}$

$\frac{K(T_1 - T_2)}{L} = h(T_2 - T)$

Substitute the values in above equation

$\frac{2.79(50- T_2)}{0.2} = 15(T_2 - 22)\\\\T_2 = 35.5^\circC$

Now heat flux through the wall can be calculated as

$q_{flux} = Q_{conduction} \\\\q_{flux} = \frac{K(T_1 - T_2)}{L}\\\\q_{flux} = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2$

Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

6 0

2 years ago