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4 years ago

Determine the positive square root of -36

2 answers:

5 0

$i=\sqrt{-1}\\\\-36=(-1)(36)\\\\\sqrt{-36}=\sqrt{(-1)(36)}=\sqrt{-1}\cdot\sqrt{36}=i\cdot6=6i\\\\Used\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\Answer:\ \boxed{\sqrt{-36}=6i}$

yuradex [85]4 years ago

4 0

Answer:

Step-by-step explanation:

$\sqrt{-36} = \sqrt{-1}\sqrt{36}\\= 6i$

The square root of a negative 1 is I, so you just take out the negative, replace it with I, then solve the square root like normal

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3 years ago

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Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

$x-13=x+1$

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

$x-13+(13)=x+1+(13)\\\\x=x+14$

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

$x-(x)=x+14-(x)\\\\0=14\ (FALSE)$

Therefore, as you can observe, the given equation has no solutions.

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4 years ago

Area and Circumference of Circles

Thepotemich [5.8K]

Pi( $\pi$ ) is the ratio of circumference to diameter for any circle.

Perimeter is the distance around a circle.

Circumference of circle $C = \pi d$ .

Perimeter of circle $= 2 \pi r$

What is circle ?

A circle is a spherical shape without boundaries or edges.

A circle is a closed, curved object with two dimensions in geometry.

Consider two small arcs AB and CD of two circles of radii x and y units, both of which make an angle of measure θ at the centers P and Q respectively.

For smaller values of θ, the arc length AB is almost equal to the length of the line segment $\bar{AB}$ . Similarly, arc CD ≅ $\bar{CD}$ .

Using the SAS rule of triangle similarity, we can say that APB and CQD are similar triangles because their angles are the same and their ratios are AP: PB = CQ: QD = 1: 1. So, it stands to reason that AB: AP = CD: CQ.

Circumference = $\pi \times$ diameter or circumference = 2 $\pi \times$ radius if this constant equals some value.