Answer:
When two spheres, each with charge Q, are positioned a distance Rapart, they are attracted to ... doubled, the electric-force between the two spheres
Answer: 43 degrees
Explanation:
The force of the crutch can be broken into components. The horizontal component of F is the static friction force keeping the crutch from sliding. The vertical component is opposing the weight and is the Normal force. Using the orientation of the angle q, we have the following
fs = Fx = F sin (angle (tita))
N = Fy = F cos (angle(tita))
Maximum angle implies maximum static friction
Therefore,
fsmax = UsN = Us x F cos(angle tita)
Where U = miyu
F sin(angle tita) = Us x Fcos (angle tita)
Sin (angle tita) / cos (angle tita) = Us
Therefore, tan (angle tita) = Us
Angle tita = tan^-1(Us) = tan^-1 (0.931) = 42.95 degrees = 43 degrees
There for Angle tita Max = 43 degrees
If a constant force is applied on a body, the body moves with constant acceleration.
Answer:
0.29 m/s due west.
Explanation:
According to newton's second law,
Net force acting on an object = mass×acceleration
From the question,
F+F₁+F₂ = ma................ Equation 1
Where F = The force generated from the engine, F₁ = Force exerted by the wind, F₂ = Force exerted due to the water, m = mass of the boat, a = acceleration of the boat.
Given: F = 4080 N , F₁ = -680 N(east), F₂ = -1160 N(east). m = 7660 kg
substitute into equation 1
4080-680-1160 = 7660(a)
2240 = 7660a
Therefore,
a = 2440/7660
a = 0.29 m/s due west.
