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bija089 [108]
4 years ago
14

Did the bird population appear to benefit from the elimination of the rattlesnakes

Physics
1 answer:
Maurinko [17]4 years ago
7 0
Yes because there's less rattlesnakes to eat them

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
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One car is sitting still the other is moving at a velocity of 4m/s. If two cars have a mass of 0.04 kg run into each other, what
Leni [432]

Answer:

p = 0.16 kgm/s

Explanation:

the initial momentum combined of the two cars and the final momentum of the paired cares are the same, so we just need to find the initial momentum

p = m1v1 + m2v2

p = 0.04*4 + 0.04*0

p = 0.04*4

p = 0.16 kgm/s

7 0
4 years ago
Wants to slide his 430g water bottle precisely 12m to land inside a Bull's Eye! If the coefficient of kinetic friction between t
AleksAgata [21]

Answer:

Ff = u M g    frictional force where u = .62

1/2 M v^2    kinetic energy of water bottle at release

Ff * d = 1/2 M v^2 = u M g d   work to stop equals initial kinetic energy

v^2 = 2 u g d = 2 * .62 * 9.8 * 12 = 146 m^2 / s^2

v = 12.1 m/s

3 0
3 years ago
A rocket in orbit just above the atmosphere is moving in uniform circular motion. The radius of the circle in which it moves is
Zinaida [17]
Centripetal acceleration is given by the formula

a_{cen}= \frac{v^2}{r}

Since we know the value of the acceleration is 9.8 m/s² and we know r, we can solve for the speed, which is the magnitude of v.  Note the value of a is just the acceleration due to gravity, which is what makes the rocket orbit and not fly off into space.

9.8 \frac{m}{s^2}=\frac{v^2}{6.381 \times 10^6m}   \\  \\ 9.8 \frac{m}{s^2} \times 6.381 \times 10^6m=v^2 \\  \\ v= \sqrt{9.8 \frac{m}{s^2} \times 6.381 \times 10^6m} =24755 \frac{m}{s}
8 0
3 years ago
The first charged object is exerting a force on the second charged object. Is the second charged object necessarily exerting a f
mario62 [17]

Answer:

Explanation:

Of course because it's Newton's Law that if body A exerts force on body B, then body B will exert equal but opposite force on body A.

HAPPY LEARNING:)

6 0
3 years ago
An experiment on the earth's magnetic field is being carried out 1.00 m from an electric cable. What is the maximum allowable cu
Whitepunk [10]

Answer:

The allowed current in the cable is 1.15 A.

Explanation:

Given that,

Distance = 1.00 m

Suppose the magnetic field is 2.3\times10^{-5}\ T and  if the experiment is to be accurate to 1.0 %

We need to calculate the current

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu_{0}}

Put the value into the formula

I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}

I=115\ A

If the experiment is to be accurate to 1.0%

Then,

We need to calculate the allowed current in the cable

I'=(1.0%)\times I

I'=\dfrac{1.0}{100}\times115

I'=1.15\ A

Hence, The allowed current in the cable is 1.15 A.

4 0
3 years ago
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