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Olegator [25]
3 years ago
5

Question 3 (10 points)

Physics
1 answer:
Fed [463]3 years ago
6 0
The answer for this is a
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As one moves farther and farther from the Sun, the distance between adjacent planets is greater.
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Read 2 more answers
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
aliina [53]

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

          W = ΔK

note that the two quantities are scalars

Work is defined by the relation

          W = F. Δx

the bold are vectors.  The displacement is

          Δx = r_f -r₀

          Δx = (11.6 i - 2j) - (4.4 i + 5j)

          Δx = (7.2 i - 7 j) m

 

          W = (4 i - 9j). (7.2 i - 7 j)

remember that the dot product

           i.i = j.j = 1

           i.j = 0

           

           W = 4  7.2 + 9  7

           W = 91.8 J

the initial kinetic energy is

           Ko = ½ m vo²

           Ko = ½ 2.0 4.0²

           Ko = 16 J

we substitute in the initial equation

          W = K_f - K₀

          K_f = W + K₀

          ½ m v_f² = W + K₀

          v_f² = 2 / m (W + K₀)

          v_f² = 2/2 (91.8 + 16)

           v_f = √107.8

          v_f = 10.38 m / s

3 0
3 years ago
Kindly explain question numbers 26 and 27
stich3 [128]

26).

The complete pattern of a pendulum is ...

-- out to one side

-- back to the center

-- out to the OTHER side

-- back to the center.

So, on the graph, the complete period is one up-loop and one down-loop.

That's <em>6 seconds</em>. (b)

27).

This question is just asking for the frequency, without using the word.

Frequency is always (1/period).  That's <em>1/6 of a second</em>. (a)

(This kinda makes sense.  If you want to do something in 6 seconds, you need to do 1/6 of it every second. Right ?)

7 0
3 years ago
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