Answer: option 1 : the electric potential will decrease with an increase in y
Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below
V = kq/y
Where k = 1/4πε0
Where V = electric potential,
k = electric constant = 9×10^9,
y = distance of potential relative to a reference point, ε0 = permittivity of free space
q = magnitude of electronic charge = 1.609×10^-19 c
From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.
We have that
V = k/y
We see the potential(V) is inversely proportional to distance (y).
This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.
This fact makes option 1 the correct answer
Answer:
the highest point the rocket reaches is 
Explanation:
Hi
First of all we are going to use 
while the engine is on, so 
.
Second, we're going to find the speed as the engine shuts off, so we have
Third, we need the time when the rocket reaches max high after engine turns off, to do that we use 
, then we isolate t, 
Finally we can find highest point by using 
Uhh? Do you have any questions or need help?
Answer: I believe it’s .25 m/s
Explanation: the speed is measured distance/ time. Which is .5 meters/ 2 seconds =0.25
