Answer:
Ionic bonds form between two or more atoms by the transfer of 1 or more electrons between atoms. Electron transfer produces negative ions called anions and positive ions called cations. ... In forming an chemical bond, the sodium atom, which is electropositive, loses its negatron to chlorine.
Explanation:
Answer:
Final temperature of calorimeter is 25.36^{0}\textrm{C}
Explanation:
Molar mass of anethole = 148.2 g/mol
So, 0.840 g of anethole =
of anethole = 0.00567 moles of anethole
1 mol of anethole releases 5539 kJ of heat upon combustion
So, 0.00567 moles of anethole release
of heat or 31.41 kJ of heat
6.60 kJ of heat increases
temperature of calorimeter.
So, 31.41 kJ of heat increases
or
temperature of calorimeter
So, the final temperature of calorimeter = 
The molecular formula =C₆H₁₂O₆
<h3>Further explanation</h3>
Given
6.00 g of a certain compound X
The molecular molar mass of 180. g/mol
CO₂=8.8 g
H₂O=3.6 g
Required
The molecular formula
Solution
mass C in CO₂ :
= 1.12/44 x 8.8
= 2.4 g
mass H in H₂O :
= 2.1/18 x 3.6
= 0.4 g
Mass O in compound :
= 6-(2.4+0.4)
= 3.2 g
Mol ratio C : H : O
= 2.4/12 : 0.4/1 : 3.2/16
= 0.2 : 0.4 : 0.2
= 1 : 2 : 1
The empirical formula : CH₂O
(CH₂O)n=180 g/mol
(12+2+16)n=180
(30)n=180
n=6
(CH₂O)₆=C₆H₁₂O₆
To determine the relative atomic mass of thallium, we multiply the molar mass of the isotopes to their corresponding relative abundance. The molecular percentages should sum up to 1. In this case, we multiply 203 by 0.295 and 205 by 0.705 and add the answers of the two. The final atomic mass is 204.41 g/mol.
The equilibrium constant k is actually the ratio of the
concentration of the products over the concentration of reactants at equilibrium. So if the
concentration of products < concentration of reactants, therefore the
constant k will be small. But if the concentration of products >
concentration of reactants, the constant k will be large. In this case the
value is too small (x10^-19), therefore we can say that the reaction favors the
reactant side:
the equilibrium lies far to the left