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Valentin [98]
3 years ago
15

Susanna was hiking in the mountains, and she discovered an interesting, shiny rock. She wondered if this sample was actually a r

ock or if it might be a mineral. As she observed it more closely, she noted that it was solid and naturally occurring, with a definite chemical composition. The sample did not appear to have a crystal structure.
Could Susanna have found a mineral? Explain why or why not.
please help me out
Chemistry
1 answer:
Zigmanuir [339]3 years ago
7 0

Answer:

Yes it is a mineral

Explanation:

Susanna has found a mineral because the five characteristics of a mineral are naturally occurring solid, crystal structure, forms by inorganic process, and definite chemical composition. Everything that was listed in the question describes the fact that its a mineral.

Brainliest would be appreciated :)

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An isotope of potassium with a half-life of roughly one billion years is often used in radioactive dating. This isotope decays t
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Answer : The chemical symbol for the element that results from this process is, (Ar) for argon.

Explanation :

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_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}

The equation for the given reaction is,

_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}

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8 0
3 years ago
An unknown compound contains only C , H , and O . Combustion of 5.60 g of this compound produced 13.7 g CO2 and 5.60 g H2O . Wha
son4ous [18]

Answer:

Empirical formula of compound  is C₄H₈O

Explanation:

Given data:

Mass of compound = 5.60 g

Mass of CO₂ = 13.7 g

Mass of H₂O = 5.60 g

Empirical formula of compound = ?

Solution:

Percentage of C:

13.7 g/5.60 g × 12/44× 100

2.45×0.273× 100 = 66.9%

Percentage of H:

5.60 g/ 5.60 g × 2.016/18 × 100

11.2%

Percentage of O:

(66.9% + 11.2%) - 100 = 21.9%

Grams atom of  C , H, O

66.9/12 = 5.6

11.2 / 1.008 = 11.11

21.9 / 16 = 1.4

Atomic ratio:

           C                 :               H           :              O

           5.6/1.4         :            11.11/1.4    :            1.4/1.4

              4                :               8            :               1

Empirical formula:

C₄H₈O

7 0
4 years ago
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