Answer:
The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451
Explanation:
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-101, K=C+273 so in this you would subtract 273 from 172
Answer:
Explanation:
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From literature, we would find that the half life of Uranium-238 is equal to 4.5x10^9 years. This is the same number of years to obtain 1/2 kg of Lead-206. Hope this answers the question. Have a nice day.
Answer:
0.5 moles of O₂
Explanation:
See the stoichiometry of the reaction:
2CO + O₂ → 2CO₂
2 moles of carbon monoxide need 1 mol of oxygen to react in order to produce 2 moles of carbon dioxide.
If I want to produce 1 mol of CO₂, I just need the half of O₂.
You will see in this rule of three. Ratio is 2:1
2 moles of CO₂ are produced by 1 mol of O₂ (Stoichiometry - reaction)
1 mol of CO₂ will be produced by ( 1 . 1) / 2 = 0.5 moles
