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bagirrra123 [75]
3 years ago
9

How many moles of calcium chloride, cacl2, can be added to 1.5 l of 0.020 m potassium sulfate, k2so4, before a precipitate is ex

pected? assume that the volume of the solution is not changed significantly by the addition of calcium chloride?
Chemistry
1 answer:
Brut [27]3 years ago
4 0
When CaSO4 → Ca2+ + SO4
So when we have Ksp = [Ca2+][SO4]

when Ksp = 4.93 x 10^-5
and [SO4] = 0.02 M 
so by substitution we can get [Ca2+] 
4.93x10^-5 = [Ca2+] [0.02]
∴ [Ca2+] = 0.0025 mol/L

∴ the moles of calcium chloride = 0.0025 mol / L * 1.5 L
                                                      = 0.00167 mol

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3 years ago
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trapecia [35]

The correct option is (b)

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Learn more about NANH2 here :-

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