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zloy xaker [14]
3 years ago
13

1.Bubbling or fizzing is an indicator of

Chemistry
1 answer:
hodyreva [135]3 years ago
6 0
D is the answer since it is changing the element.
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How many major Foods or food groups accounts for 90% of food allergens?​
kow [346]

Answer:

Eight foods are responsible for 90 percent of all reactions: peanut, tree nut, milk, egg, fish, shellfish, soy, and wheat.

hope it helped

6 0
2 years ago
This electron cloud model of aluminum has _______ energy levels with _______ electrons on its outer energy level. A) 1, 2 B) 2,
Talja [164]

Answer:

C

Explanation:

Have anice day

7 0
3 years ago
Help please I need the answer
nexus9112 [7]

Answer:

                    Polyatomic Ionic Compound

Explanation:

                     In given statement the compound given is called as Sodium oleate this means that when Oleic acid is treated with NaOH then it forms.

                     In chemistry there are few species which are involved in the formation of compounds.

  (i) Atoms:

                  It is very common that atoms of different elements combine to form compound through covalent bond. For example, H₂, O₂, N₂, F₂ e.t.c.

   (i) Ions:

                  Other than covalent compounds we have ionic compounds. Ionic compounds are made up of ions. These ions forming the ionic compounds can be monatomic like Na⁺, Br⁻, Mg²⁺, Al³⁺, N⁻³ or they can be polyatomic like CO₃²⁻, SO₄²⁻, NH₄⁺, PO₄³⁻ e.t.c.

    (iii) Polyatomic Ions:

                                     In polyatomic ions we find a charge on a molecule which contains two or more atoms bonded covalently. Hence, in given compound we have a long chain of molecule containing a negative charge neutralized by opposite +ve charged sodium ion. Hence, Sodium oleate is a polyatomic ionic compound.

5 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
2 years ago
Which method is used to make the salt copper(II) sulfate?
Tanzania [10]

Answer:

Its B. Dilute acid + carbonate

Explanation:

hope it helps !!

3 0
2 years ago
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