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zloy xaker [14]
3 years ago
13

1.Bubbling or fizzing is an indicator of

Chemistry
1 answer:
hodyreva [135]3 years ago
6 0
D is the answer since it is changing the element.
You might be interested in
Nearly every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element
baherus [9]

Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

Similarly, every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element in the ⁺2 state because of inert pair effect.

<h3>What is Inert pair effect? </h3>

The inert-pair effect is defined as the tendency of two electrons in the outermost atomic s-orbital almost remain unshared in the compounds of the post-transition metals.

<h3>How we calculate Oxidation state? </h3>
  • Each atom in an element either be in its uncombined or free state has oxidation number of zero. Such as each atom in H₂, Cl₂ , P4, ,O₂ , Na, Al, O3, S8, and Mg, all have an oxidation number zero.
  • The oxidation state of ions that comprise of only one atom is the actual charge on the ion.
  • The oxidation state of hydrogen is +1, excluding when it is bonded to metals having two elements. For example, CaH2, its oxidation state is –1.
  • Fluorine and other halogens have an oxidation state equal to –1 when they appear as a form of halide ions in their compounds.

Since the inert pair effect increases as we go down the group and become more predominant, therefore, the stability of +2 oxidation state goes on increasing down the group. Therefore, gallium, indium are mostly found in +1 oxidation state.

Thus, we concluded that Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

learn more about oxidation state:

brainly.com/question/25551544

#SPJ4

4 0
2 years ago
Determine the number of protons, electrons, neutrons, valence electrons and valency in Oxygen atom (O) and Oxide ion (O2-). Comp
wolverine [178]

Answer:

<em />

<em>                    Atom (O)           Ion (O²⁻)</em>

<em>Protons             8                       8</em>

<em>Electrons          8                      10</em>

<em>Neutrons          8                       8   </em>      ← only for the oxygen-16 isotope.

* The number of neutrons depends on the specific isotope. It is equal to the mass number of the isotope less the number of protons.

Explanation:

<em>Oxygen</em> is the element with atomic number 8. That means that the oxygen atoms have 8 protons.

Protons have relative positive charge equal to +1 and electrons have relative negative charge -1: same magnitude opposite sign.

Thus, the neutral oxygen, O, has also 8 electrons and 8 protons.

As per the number neutrons it depends on the specific isotope.

The isotopes are identified by the mass number, which is the number of protons plus neutrons. For instance, oxygen-16 isotope has mass number 16, 8 protons and 8 neutrons, while oxygen-15 isotope has mass number 15, 8 protons and 7 neutrons.

Oxide ion O²⁻ is the oxygen ion with -2 charge, meaning that it has 2 more electrons than protons. Then, it has 8 protons and 10 electrons, again the number of neutrons depend of the specific isotope.

The stability of an atoms or ion refers to its trend to remain in the same state or react to form another species. The ions O²⁻ are less stable than the neutral atoms O, because the negative charge will be attracted to any positive ion so ti will react faster than the neutral oxygen atom (O).

8 0
4 years ago
N2(g) + 2H(g) -&gt; N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

6 0
3 years ago
What is <br> 78.432 miles x 322.3 miles
Phoenix [80]
That would be 25,270.7904 miles
8 0
3 years ago
Which has a greater momentum, a car or a bike moving at the same speed​
blsea [12.9K]

The car has greater momentum because it has more mass than a bike, even if they have the same speed. I hope this helped! :-)

5 0
3 years ago
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