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Nat2105 [25]
3 years ago
14

How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of cal

cium metal? (2 points)
Ca (s) + 2HCl (aq)yields CaCl2 (aq) + H2 (g)
Chemistry
1 answer:
stich3 [128]3 years ago
4 0

<u>Answer:</u>

2400 mL

<u>Explanation:</u>

Ca + 2HCl \implies CaCl_2 + H_2

According to this equation, the stoichiometric ratio between Ca and HCl for the complete reaction is 1:2.

We know that the number of moles of Ca can be calculated using the mole formula. (<em>number of moles = mass / molar mass</em>)

Moles of Calcium = \frac{60}{40} = 1.5 mol

So the moles of HCl = 1.5 \times 2 = 3.0 mol

<em>Volume of HCl solution = Moles of HCl/ concentration of HCl</em>

Volume of HCl solution = \frac{3}{1.25} = 2400 mL

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450g of chromium(iii) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS
ExtremeBDS [4]

Answer:

1597.959 g  

Explanation:

Given Data:

Amount of Cr₂(SO₄)₃ = 450 g

Amount of potassium phosphate K₃PO₄ = in Excess

grams of potassium sulfate K₂SO₄= ?

Solution

The Reaction will be

                 Cr₂(SO₄)₃ + 2K₃PO₄  ----------> 3K₂SO₄ + 2CrPO₄

Information that we have from reaction

                Cr₂(SO₄)₃ + 2K₃PO₄  ----------> 3K₂SO₄ + 2CrPO₄

                    1 mol          2 mol                   3 mol

we come to know from the above reaction that

1 mole of chromium(iii) sulfate (Cr₂(SO₄)₃) react with 2 mole of potassium phosphate (K₃PO₄) to produce 3 mole of K₂SO₄

We also know that

molar mass of Cr₂(SO₄)₃ = 147 g/mol

molar mass of K₃PO₄ = 212 g/mol

molar mass of K₂SO₄ = 174 g/mol

if we represent mole in grams then

      Cr₂(SO₄)₃             +       2K₃PO₄          ----------> 3K₂SO₄ + 2CrPO₄

       1 mol (147 g/mol)         2 mol  (212 g/mol)      3 mol  (174g/mol)

So, Now we have the following details

          Cr₂(SO₄)₃  +  2K₃PO₄          ----------> 3K₂SO₄ + 2CrPO₄

              147 g         424 g                           522 g

So,

we come to know that 147 g of Cr₂(SO₄)₃ combine with 424 g of 2K₃PO₄ produce  522 g of K₂SO₄

So now we calculate that how many grams of potassium sulfate will be produced

Apply unity formula

              147 g of  Cr₂(SO₄)₃  ≅ 522 g of K₂SO₄

              450 g of  Cr₂(SO₄)₃  ≅ ? g of K₂SO₄

by doing cross multiplication

g of K₂SO₄ =522 g x 450 g / 147 g

g of K₂SO₄ =  1597.959 g

So the write answer is  1597.959 g  

***Note: By calculation it is obvious that the correct answer is  1597.959 g  

8 0
3 years ago
What are some examples of how matter moves through a cycle on earth ​
olganol [36]

Answer:

Ocean, lakes and rivers. Are all liquids.

Explanation:

Ocean, lakes and rivers. Are all liquids. Snow starts off as a liquid, evaporates into a gas and camoes back as snow.

4 0
3 years ago
In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced if 5
Rufina [12.5K]

Answer:

The full amount (5.00 g) will be dissolved in 1 L of water at 25°C.

Explanation:

The molecular weight (MW) of Vanillin (C₈H₈O₃) is calculated from the chemical formula as follows:

MW(C₈H₈O₃) = (12 g/mol x 8) + (1 g/mol x 8) + (16 g/mol x 3) = 152 g/mol

If 0.070 mol of C₈H₈O₃ are soluble per liter of water at 25°C, the maximum mass that can be dissolved in 1 L is:

0.070 mol x 152 g/mol = 10.64 g

Since 5.00 g is lesser than the maximum amount that can be dissolved (10.64 g), the added amount will be completely dissolved in 1 L of water at 25°C.

7 0
2 years ago
Sterling silver is 92.5% silver and 7.5% copper. Its density is 10.25 g/cm3. A sterling silver pendant is added to a graduated c
Mariulka [41]

From the information given:

  • The volume of the graduated cylinder = 50.0 mL
  • when a sterling silver pendant is added, the volume increases to = 61.3 mL

∴

The volume of the sterling silver pendant is:

= 61.3 mL - 50.0 mL

= 11.3 mL

Since, 1 mL = 1cm³

Then;

11.3 mL = 11.3 cm³

  • the density of the sterling silver = 10.25 g/cm³

Using the relation for Density; i.e.

\mathbf{Density = \dfrac{mass}{volume}}

\mathbf{10.25 \ g/cm^3= \dfrac{mass}{11.3  \ cm^3}}

mass = 10.25 g/cm³× 11.3 cm³

mass of the sterling silver = 115.825 grams

Recall that sterling silver has:

  • 92.5% silver and;
  • 7.5% copper

∴

The mass of the copper contained in the sterling silver pendant can be calculated as:

\mathbf{= \dfrac{115.825  \ g \times 7.5}{100}}

= 8.687 grams

Therefore, we can conclude that the mass of the copper contained in the sterling silver pendant is 8.687 grams

Learn more about the relation between Density, Mass, and Volume here:

brainly.com/question/24386693?referrer=searchResults

4 0
2 years ago
What is the best way to reduce the activation energy?
Ksivusya [100]

Answer:

The method of hurrying up a reaction by decreasing its activation energy is called as catalysis, and the circumstance that's added to reduce the activation energy is termed as the catalyst.

Explanation:

Organic catalysts are named as enzymes. Enzymes are protein particles in cells which act as catalysts. Enzymes are proteid particles in groups which act as catalysts. Enzymes rush up biochemical effects in the thing but do not become used up in the method. Nearly all biochemical effects in living things require enzymes. Among an enzyme, biochemical effects go extremely quicker than they would without the enzyme.

5 0
3 years ago
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