Answer:
252J
Explanation:
Given parameters:
Distance = 72m
Force = 3.5N
Unknown:
Work done on the house = ?
Solution:
Work done is the force applied to move a body through a particular distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 3.5 x 72 = 252J
Answer:
The frequency would not change because the frequency of a simple pendulum does not depend on mass.
Explanation:
Answer:
Explanation:
<u>Kinematics equation for first Object:</u>
![y(t)=y_{o}+v_{o}t-1/2*g*t^{2}](https://tex.z-dn.net/?f=y%28t%29%3Dy_%7Bo%7D%2Bv_%7Bo%7Dt-1%2F2%2Ag%2At%5E%7B2%7D)
but:
The initial velocity is zero
![y_{o}=20m](https://tex.z-dn.net/?f=y_%7Bo%7D%3D20m)
it reach the water at in instant, t1, y(t)=0:
![0=y_{o}-1/2*g*t_{1}^{2}](https://tex.z-dn.net/?f=0%3Dy_%7Bo%7D-1%2F2%2Ag%2At_%7B1%7D%5E%7B2%7D)
![t_{1}=\sqrt{2y_{o}/g}=\sqrt{2*20/9.81}=2.02s](https://tex.z-dn.net/?f=t_%7B1%7D%3D%5Csqrt%7B2y_%7Bo%7D%2Fg%7D%3D%5Csqrt%7B2%2A20%2F9.81%7D%3D2.02s)
<u>Kinematics equation for the second Object:</u>
The initial velocity is zero
![y(t)=y_{o}+v_{o}t-1/2*g*t^{2}](https://tex.z-dn.net/?f=y%28t%29%3Dy_%7Bo%7D%2Bv_%7Bo%7Dt-1%2F2%2Ag%2At%5E%7B2%7D)
but:
![y_{o}=20m](https://tex.z-dn.net/?f=y_%7Bo%7D%3D20m)
it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s
![0=y_{o}+v_{o}t_{2}-1/2*g*t_{2}^{2}](https://tex.z-dn.net/?f=0%3Dy_%7Bo%7D%2Bv_%7Bo%7Dt_%7B2%7D-1%2F2%2Ag%2At_%7B2%7D%5E%7B2%7D)
The velocity is negative, because the object is thrown downwards.
Answer:
See below
Explanation:
a) 500 cm^3 * .90 gm/cm^3 = 450 gm of oil
b) 450 gm + 80 gm = 530 gm of oil and bottle