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3 years ago

5

Which of the following describes a situation in which the total distance a tennis player travels is 0 meter from his starting po

int?

2 answers:

gregori [183]3 years ago

6 0

Can u list out the "following?"

Zigmanuir [339]3 years ago

4 0

I think the answer is C im doing the quiz rn and please respond back if u got the right answer and ell me what it is. And mark brainlest

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How many ways can you flip a coin and roll a standard dice?

ozzi

Answer:

its probably 6×2=12 times

coin has 2 sides

dice has 6 faces

7 0

3 years ago

I NEED HELP PLEASE, THANKS! :) Use the graph to determine the domain and range of the relation, and state whether the relation i

Mandarinka [93]

Answer:

Domain: All numbers greater than or equal to 0. By definition, the domain of a graph, is the possible x values.

Range: All real numbers. By definition, the range is all possible x values.

Not a function. A function has y value for every x value.

3 0

3 years ago

Please help me on this!

yanalaym [24]

Answer:

${9}^{ - 8}$

Step-by-step explanation:

$\frac{ {9}^{ - 5} }{ {9}^{3} }$

${9}^{ - 5 - (3)}$

${9}^{ - 5 + (- 3)}$

${9}^{ - 8}$

6 0

3 years ago

You decide to take your car on a drive through Canada, where gas is sold in liters and distances are measured in kilometers. Sup

12345 [234]

Answer:

the no of liters required is 50.55 liters

Step-by-step explanation:

Given that

The car gas efficiency is 23.0 mi/gal

distance is 495 km

1 gal = 3.78 L

1 km = 0.6214 mi

We need to find out the no of liters of gas that would needed to complete a trip

So,

= (495 × 3.78 × 0.6214) ÷ (23)

= 50.55 Liters

hence, the no of liters required is 50.55 liters

7 0

3 years ago

Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an

Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean $\mu$ , standard deviation $\sigma$ .

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

8 0

2 years ago