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tino4ka555 [31]
3 years ago
13

Currently, 118 elements are listed on the periodic table. One thing that each of these elements has in common is that they are c

omposed of what?
A. Carbon
B. Energy
C. Atoms
D. Mixtu
Chemistry
1 answer:
zimovet [89]3 years ago
4 0

The answer is C. Atoms. Atoms make up everything.

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Separating techniques - Chromatography
vodomira [7]

The method that can be used to separate the mixture is chromatography.

<h3>What is chromatography?</h3>

"Chromatography" is obtained form a Greek word which literarily means, color writing. It is a method of separation which is common in separating a mixture of pigments.

To obtain the colors used, two solvents are mixed and the sample ink is dissolved in the solvents then spotted on a thin layer and put into a TLC chamber then the chromatogram is allowed to develop.

The various components of the pigment will appear on the chromatogram and can be identified using spectrophotometry. The Rf values of each component can also be used to identify it.'

Learn more about chromatography: brainly.com/question/26491567

7 0
2 years ago
Do you know any of these?
bulgar [2K]
The second one is no
6 0
3 years ago
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The diagram below represents the organizational levels of living things.
Tasya [4]

Answer: its vein

Explanation:

3 0
3 years ago
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Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -&gt; 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
3 years ago
At what temperature and pressure can all three phases of water exist simultaneously?
Rzqust [24]
Thirty seven I think
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3 years ago
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