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azamat
3 years ago
6

Crystals of a chemical in a lab slowly disappear from their container they do not become liquid. What change of state is this an

example of?
Chemistry
1 answer:
Olenka [21]3 years ago
8 0
The change of state that has been given in the question is called sublimation. It is actually the process in which a solid gets directly converted to gas without changing into liquid. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
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Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in
Anit [1.1K]

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

<h3>What is displacement?</h3>

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

<h3>Displacement of the waves after 0.1 s</h3>

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 0 m
  • wave A from left will stop at point -1 m
  • wave C from right will stop at point 0 m
  • wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm =  2cm

<h3>Displacement of the waves after 0.2 s</h3>

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 1 m
  • wave A from left will stop at point 0 m
  • wave C from right will stop at point -1 m
  • wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

8 0
2 years ago
A fixed mass of gas has a volume of 92 cm cube and 3 degrees Celsius. What will be its volume at 18 degrees celsius if the press
8090 [49]

Answer:

94.8454

Explanation:

Let volume be V

Let Temperature be T

V1= 92

T1= 3C but to kelvin 273+3= 300K

V2= ?

T2= 18 C but to kelvin 18+273= 291

\frac{v1}{t1}  =  \frac{v2}{t2}

\frac{92}{300}  =  \frac{v2}{291}

v2 \times 300 = 92  \times 291

v2 =  \frac{92 \times 291}{300}

v2 = 94.8454

3 0
3 years ago
In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)
Natalka [10]

<u>Answer:</u> The molarity of Cr^{3+} ions in the solution is 0.299 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For chromium (III) acetate:</u>

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol

1 mole of chromium (III) acetate (Cr(CH_3COO)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of acetate (CH_3COO^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles

  • <u>For chromium (III) nitrate:</u>

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol

1 mole of chromium (III) nitrate (Cr(NO_3)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of nitrate (NO_3^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles

  • <u>For chromium cation:</u>

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+} ions in the solution is 0.299 M

5 0
3 years ago
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tankabanditka [31]
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3 0
3 years ago
2 What is the gram-formula mass of Ca(OH)2?
Verizon [17]

Answer:

<em><u>The</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>Answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>Number</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>7</u></em><em><u>4</u></em><em><u> </u></em><em><u>g</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>mole</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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3 years ago
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