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Fofino [41]
3 years ago
10

Type in the correct values to correctly represent the valence electron configuration of magnesium: AsB A = B =

Chemistry
2 answers:
erik [133]3 years ago
7 0
<h2>Answer : The correct answer will be A =3 and B =2 as the electron configuration of Mg will be as [Ne] 3s^{2} where A is 3 and B is 2.</h2><h3>Explanation : </h3>

Magnesium has atomic number as 12. The complete electron configuration will be as 1s^{2}2s^{2}2p^{6}3s^{2}.

which can be abbreviated as[Ne] 3s^{2} as the electron configuration resembles to that of neon element.

In the outermost shell the electron in 3 s orbital is only 2. So, therefore 3 is the orbital of S and there are 2 electrons in it.

Alexxandr [17]3 years ago
5 0
The correct answer would be,
A= 3 
B=2
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HNO3 is a Bronsted-Lowry acid. What will this substance form when it donates a proton?
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The HNO3 is considered to be a Bronsted - Lowry acid, when this substance 'HNO3', will donate a proton, then it will form another substance. It will form two substances when the proton is donated in the water molecule. The two substances that will be formed is a nitrate iron and a hydronium ion.
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3 years ago
.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f
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Answer : The value of K_c for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)

The expression of K_c will be,

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

First we have to calculate the concentration of Br_2,Cl_2\text{ and }BrCl.

\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M

Now we have to calculate the value of K_c for the given reaction.

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

K_c=\frac{(0.6)^2}{(1)\times (1)}

K_c=0.36

Therefore, the value of K_c for the given reaction is, 0.36

6 0
3 years ago
Read 2 more answers
5. Why are lonic compounds good conductors of electricity?
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Answer:

The options are unclear, however, the correct option is:

Aqueous solutions of ionic compounds cause to dissociate, hence, ions are free to conduct electricity

Explanation:

Ionic compounds are compounds formed from ions (charged atoms). For example, NaCl is an ionic compound from the following ions; Na+ (cation) and Cl- (anion). One characteristics of ionic compounds is their ability to dissociate into the ions that form them when in an aqueous solution i.e. NaCl will dissociate into Na+ and Cl- when in an aqueous solution.

These disssociated ions are free to conduct electricity, hence, making ionic compounds good conductors of electricity.

6 0
3 years ago
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Explanation :

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or,

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As we are given :

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So,

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