0.1324 ×10^24 atoms of carbon are in 2.65 g of carbon
Explanation:
Converting the grams of carbon to the moles of carbon.
Divide the mass (2.65 g) by 12.011 g/mol which is the molecular weight of carbon,
2.65 g / 12.011 g/mol=0.220 moles of carbon
Then, convert moles of carbon to atoms of carbon using Avogadro's constant (6.022×10^23 atoms per mole)
0.220 moles × 6.022×10^23 atoms / 1 mole = 0.1324 ×10^24 atoms
0.1324 ×10^24 atoms of carbon are in 2.65 g of carbon
Answer:
b molecular orbital therory
Spears and knives
(Plz thank me if this helped)
Answer:
The product would have more acidity than Diethyl malonate
Explanation:
For this question, first, we have to start with the structure of the bromination reaction. <u>The bromination would add a "Br" atom</u> in the middle carbon between the ester groups. Therefore, the molecule produced would be <u>diethyl 2-bromomalonate</u> and the formula of this compound fits with the reported by the question: ![C_7H_1_1BrO_4](https://tex.z-dn.net/?f=C_7H_1_1BrO_4)
Now, if we have to analyze the acidity we have to check the <u>most acidic hydrogen</u>. In this case, is the "H" in the middle carbon (red hydrogen). In the Diethyl malonate, we have an <u>inductive effect</u> caused by the carbonyl groups on each side of the middle carbon. In the diethyl 2-bromomalonate, we have this same inductive effect plus the Br atom bonded to the same carbon. Therefore, would be <u>easier to remove the hydrogen</u>. So, diethyl 2-bromomalonate would ba more acidity than Diethyl malonate.
See figure 1
I hope it helps!