Answer:
100 J, 225 J
Explanation:
The kinetic energy of an object is given by:

where
m is the mass of the object
v is the velocity of the object
In this problem, the initial kinetic energy of the object is
K = 25 J
Then, the velocity is doubled, which means
v' = 2v
Therefore, the new kinetic energy will be

Therefore, the kinetic energy has quadrupled:

Later, the velocity is tripled, which means
v'' = 3v
Therefore, the new kinetic energy will be

Therefore, the kinetic energy has increased by a factor of 9:
