The answer is to your question is force
Answer:
The ball experiences the greater momentum change
Explanation:
The momentum change of each object is given by:
where
m is the mass of the object
v is the final velocity
u is the initial velocity
Both objects have same mass m and same initial velocity u. So we have:
- For the ball, the final velocity is
Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is
- For the clay, the final velocity is
since it sticks to the wall. So, the change in momentum is
So we see that the greater momentum change (in magnitude) is experienced by the ball.
I believe the answer is up and down :)
The image distance is 59.2 cm and the image is real and small.
<h3>
Image distance</h3>
The distance of the image formed by the convex or converging lens is determined by applying the following lens equation.
1/f = 1/u + 1/v
where;
- f is the focal length = 34 cm
- u is the object distance = 80 cm
- v is the image distance = ?
1/v = 1/f - 1/u
1/v = 1/34 - 1/80
1/v = 0.0294 - 0.0125
1/v = 0.0169
v = 1/0.0169
v = 59.2 cm
Thus, the image distance is 59.2 cm and the image is real and small.
Learn more about convex lens here: brainly.com/question/10153605
Answer:
19.5 m/s
87.8 m
Explanation:
The acceleration of block one is:
∑F = ma
-m₁gμ = m₁a
a = -gμ
a = -(9.8 m/s²) (0.22)
a = -2.16 m/s²
The velocity of block one just before the collision is:
v² = v₀² + 2aΔx
v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)
v = 7.63 m/s
Momentum is conserved, so the velocity of block two just after the collision is:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
m₁u₁ = m₂v₂
(18.5 kg) (7.63 m/s) = (7.25 kg) v
v = 19.5 m/s
The acceleration of block two is also -2.16 m/s², so the distance is:
v² = v₀² + 2aΔx
(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx
Δx = 87.8 m
