a. We can calculate the amount of work by calculating the area under the graph.
first area (rectangular): 2.5 x 6 = 15
second area(trapezoid): 1/2 x (6+10) x 2.5 =20
total work done: 35 J
b. the force was first applied = 6 N
F = m.a
a = 6 : 3 = 2 m/s²
vf²=vi²+2as
vf²=6²+2.2.5
vf²=56
vf=7.5 m/s
Answer:
In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.
Answer:
the simplified expression is written as 3.4 x 10³
Explanation:
Given expression;

in scientific notation, the expression is simplified as;

Therefore, in scientific notation, the simplified expression is written as 3.4 x 10³
Answer:
Explanation:
Given:
volume of urine discharged, 
time taken for the discharge, 
diameter of cylindrical urethra, 
length of cylindrical urethra, 
density of urine, 
a)
we have volume flow rate Q:
& 
where:
cross-sectional area of urethra
velocity of flow




b)
The pressure required when the fluid is released at the same height as the bladder and that the fluid is at rest in the bladder:


