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andre [41]
3 years ago
6

What is an object’s acceleration if it is moving at 30 m/s and comes to a stop in 5 s? –30 m/s2 –6 m/s2 30 m/s2 6 m/s2

Physics
2 answers:
Readme [11.4K]3 years ago
7 0

Answer:

The acceleration is  -6 m/s2

Explanation:

The equation for the speed of a body is

         V = Vo + a t

Where

Vo is the initial velocity, a is the acceleration and t is the time,

When the body stops the speed is zero

       0 = Vo + a t

        a = Vo / t

substitute values

        a = - 30/5

        a = - 6 m/s2

The negative sign indicates that acceleration opposite movement

Tanya [424]3 years ago
3 0

Answer:32m/s

Explanation:

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The light bulb would glow brighter.

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1 year ago
A 500-N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
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Answer:

W₂= 10000 N

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area (A2) of the piston:

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\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

F_{2} = \frac{F_{1}*A_{2}  }{A_{1}}  Equation (1)

Data

W₁ = weight sits on the small piston

F₁ = W₁= 500 N

A₁ = 2.0 cm²

A₂ = 40 cm²

Calculation of the weight  (W₂) can the large piston support

We replace data in the equation (1)

F_{2} = \frac{(500)*(40) }{2}

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3 years ago
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Answer:

 θ = 36°

Explanation:

given,

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magnitude of force = ?

direction of force = ?

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F = \sqrt{22.8^2 + 16.6^2}

F = \sqrt{795.4}

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\theta = tan^{-1}(\dfrac{16.6}{22.8})

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2 years ago
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