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andre [41]
3 years ago
6

What is an object’s acceleration if it is moving at 30 m/s and comes to a stop in 5 s? –30 m/s2 –6 m/s2 30 m/s2 6 m/s2

Physics
2 answers:
Readme [11.4K]3 years ago
7 0

Answer:

The acceleration is  -6 m/s2

Explanation:

The equation for the speed of a body is

         V = Vo + a t

Where

Vo is the initial velocity, a is the acceleration and t is the time,

When the body stops the speed is zero

       0 = Vo + a t

        a = Vo / t

substitute values

        a = - 30/5

        a = - 6 m/s2

The negative sign indicates that acceleration opposite movement

Tanya [424]3 years ago
3 0

Answer:32m/s

Explanation:

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Suppose a 1300 kg car is traveling around a circular curve in a road at a constant
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Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

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We need to find the magnitude of the unbalanced force that steers the car out of its natural straight-  line path. The force is called centripetal force. It can be given by :

F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N

So, the force has a magnitude of 4212 N

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3 years ago
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is
jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

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3 years ago
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According to newton's first law, massive objects have larger inertia than small objects, which means it takes more force to move bigger things than smaller ones.
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3 years ago
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