1.List one extensive and one intensive property of marker ink.
Intensive property is a property that is independent of the amount of sample such as the color of the ink. Extensive property is the opposite which is dependent to the amount such as volume.
2.Define mixture.
Mixture is a system that contains two or more substances which are agitated but not chemically bonded.
3.Is tap water a heterogeneous or homogenous mixture?
Tap water is a homogenoeus mixture because it has uniform properties in every sample you get.
4.Is isopropyl alcohol (rubbing alcohol) a heterogeneous or homogenous mixture?
I think the rubbing alcohol is a homogeneous mixture since it has uniform properties as well.
Answer:
so with every stoichiometry problem with a mass it will make it so you can do the conversion factor with reactants or products.
if you dont understand unit conversions try to study how to set it up. anyways
a.) C12H22O11 has a mass of 342.01 Grams per mole
divide 1.202 G by 342.01 G to get 0.004 miles
b.) you're just taking the AMU of each element in the chemical multiply it by how many there is of it in the chemical, then divide it by the mass of a mole of the chemical.
c.) you take your answers of part b and multiply them by Avogadro's number
Solution :
From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .
Moles of KBr in 102 g of potassium bromide.
n = 102/119.002
n = 0.86 mole.
So, number of miles of KCl produced are also 0.86 mole.
Mass of KCl produced :
Hence, this is the required solution.
2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O
Molar masses
C3H6: 42.08 g/mol
NH3: 17.03 g/mol
O2: 32 g/mol
CH3H3N: 53.06 g/mol
H2O: 18 g/mol
# of moles
C3H6: 15.0 g / [42.08 g/mol] = 0.356 mol
NH3: 5.00 g / [17.03 g/mol] = 0.294 mol
O2: 10.0 g / [32 g/mol] = 0.313 mol
Now wee need to find the limitant reactant
The theoretical proportion is 2:2:3, equivalent to 1:1:1.5
The proportion ot the given gases is 0.356 : 0.294 : 0.313, dividing by 0.294 that is equivalent to: 1.2 : 1 : 1.06, where you see that O2 is below the theoretical proportion and it is the limitant reactant.
Now, from the equation you have 3 mol of O2 produces 2 mol of acrylonitrile (C3H3N)
Then you will obtain 0.313 * 2/3 = 0.209 mol acrylonitrile
The mass is 0.209mol * 53.06 g/mol = 11.07 g acrylonitrile
Answer: 11.07 g