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xenn [34]
3 years ago
7

One example of a chemical used in toothpaste is ________

Chemistry
1 answer:
kap26 [50]3 years ago
8 0
Water is a chemical used in toothpaste.

Fluoride in the form of sodium fluoride is another chemical.
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Balance <br><br> _Mg + _HCL = _MgCl2 + H2
Pavel [41]
_Mg + _HCL = _MgCl2 + H2
Separate the terms on each side: 

_Mg + _HCl = _MgCl2 + H2

Mg- 1                 Mg-1
               
H-1                    H-2

Cl-1                    Cl-2

Mg is balanced on both sides so move on to the next (put a 1 in the space). 

1Mg

There are two H's and two Cl's on the results side, so to balance the equation put a 2 as a coefficient for HCl and it'll all balance out.

2HCl

Balamced equation will be: 

 1Mg + 2HCL = 1MgCl2 + H2
5 0
3 years ago
Read 2 more answers
Explain how you determine the freezing point of a solution that does not have a well-defined transition in the cooling curve.
Sophie [7]

This question is asking for a method for the determination of the freezing point in a solution that does not have a noticeable transition in the cooling curve, which is basically based on a linear fit method.

The first step, would be to understand that when the transition is well-defined as the one on the attached file, we can just identify the temperature by just reading the value on the graph, at the time the slope has a pronounced change. For instance, on the attached, the transition occurs after about 43 seconds and the freezing point will be about 4 °C.

However, when we cannot identify a pronounced change in the slope, it will be necessary to use a linear fit method (such as minimum squares) to figure out the equation for each segmented line having a significantly different slope and then equal them so that we can numerically solve for the intercept.

As an example, imagine two of the segmented lines have the following equations after applying the linear fit method:

y=-3.5 x + 25\\\\y=-0.52 x + 2

First of all, we equal them to find the x-value, in this case the time at which the freezing point takes place:

-3.5 x + 25=-0.52 x + 2\\\\-3.5 x+0.52 x =2-25\\\\x=\frac{-23}{-2.98}=7.72

Next, we plug it in in any of the trendlines to obtain the freezing point as the y-value:

y=-3.5 (7.72) + 25\\\\y = 1.84

This means the freezing point takes place after 7.72 second of cooling and is about 1.84 °C. Now you can replicate it for any not well-defined cooling curve.

Learn more:

  • brainly.com/question/22818252
  • brainly.com/question/9680530

7 0
3 years ago
The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a
melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

                          (100ml - 1.468 ml)

                        = 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

          Amount of water = \frac{1.468 ml \times 23 ml}{98.532 ml}

                                       = 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

                Mg + H_{2}O \rightarrow Mg(OH)_{2}

Molar mass of Mg = 24.305 g

Molar mass of H_{2}O = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

           Amount of Mg = \frac{24.305 g \times 0.3427 ml}{18 g}  

                                    = 0.462 g

   

6 0
3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
Katyanochek1 [597]

Answer:

a=64.7mg

Explanation:

Hello,

In this case, we need to remember that for the required time for a radioactive nuclide as radium-226 to decrease to one half its initial amount we are talking about its half-life. Furthermore, the amount of remaining radioactive material as a function of the half-lives is computed as follows:

a=a_0(\frac{1}{2} )^{\frac{t}{t_{1/2}} }

Therefore, for an initial amount of 100 mg with a half-life of 1590 years, after 1000 years, we have:

a=100mg(\frac{1}{2} )^{\frac{1000years}{1590years} }\\\\a=64.7mg

Best regards.

4 0
3 years ago
Low frequency waves have longer wavelength true or false
kap26 [50]

Answer:

True

Explanation:

Since the waves have low frequency that means the wavelength is going to be longer. Hope this helps

5 0
2 years ago
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