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mr Goodwill [35]
3 years ago
7

Two objects of equal mass are a fixed distance apart. If the mass of each object could be tripled, the gravitational force betwe

en the objects would....
Physics
1 answer:
antiseptic1488 [7]3 years ago
5 0

gravitational force between two objects is given as

F = G m₁ m₂/r²

where m₁ = mass of first object , m₂ = mass of second object , r = distance between the two objects .

Initial case :

m₁ = m₂ = m

gravitational force between the objects is given as

F = G m²/r²

Final Case :

m₁ = m₂ = 3 m

new gravitational force between the objects is given as

F' = G (3m)²/r²

F' = 9 G m²/r²

F' = 9 F

hence the gravitational force between the two objects becomes 9 times.

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The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron
FrozenT [24]

Answer:

<em>Speed of the electron is 2.46 x 10^8 m/s</em>

<em></em>

Explanation:

momentum of the electron before relativistic effect = M_{0} V

where M_{0} is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = M_{0}/ \sqrt{1 - \beta ^{2}  }

where

\beta = V/c

c  is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> M_{0}V/ \sqrt{1 - \beta ^{2}  }

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75M_{0} V = M_{0}V/ \sqrt{1 - \beta ^{2}  }

the equation reduces to

1.75 = 1/ \sqrt{1 - \beta ^{2}  }

square both sides of the equation, we have

3.0625 = 1/(1 - \beta ^{2} )

3.0625 - 3.0625\beta ^{2} = 1

2.0625 = 3.0625\beta ^{2}

\beta ^{2} = 0.67

β = 0.819

substitute for  \beta = V/c

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = <em>2.46 x 10^8 m/s</em>

6 0
4 years ago
Laser light has a great deal of______ a. chemical b. heat c. potential d. sound energy.??​
svet-max [94.6K]

Answer:

b. heat

Explanation:

4 0
3 years ago
What is latent heat? Group of answer choices Energy released when water evaporates. Energy hidden in water vapor in the air. Ene
Andrews [41]

Answer:

Energy absorbed or hidden when water evaporates

Explanation:

The heat that is required to make a phase change is known as latent heat.

A phase change occurs when matter changes state. For example from solid to liquid, from liquid to gas, among others.

When changing from liquid to gas (for example when water evaporates), the heat necessary for this to happen is called latent heat of vaporization. The word latent means hidden, because a change in temperature is not perceived during the phase change, even when heat is being added, thus it is said that the heat is hidden or latent.

So the answer is:

  • Energy absorbed or hidden when water evaporates.

*Another type of latent heat is the latent heat of fusion, which is when a solid becomes liquid.

7 0
4 years ago
A circuit has a current of 1.2 A. If the voltage decreases to one-third of its original amount while the resistance remains cons
lapo4ka [179]
Consider the formula ...

Current  =  (voltage) / (resistance) .

If the resistance doesn't change, then the current is
directly proportional to the voltage.

If the voltage decreases to 1/3 of what it used to be,
then the current does the same thing.

1.2 A  ---->  0.4 A
6 0
3 years ago
A parallel-plate capacitor with circular plates of radius R is being discharged. The displacement current through a central circ
Dvinal [7]

Answer:

The discharging current is I_d  =  36.8 \ A

Explanation:

From the question we are told that  

     The radius of each circular plates is  R

     The displacement current is  I  = 9.2 \ A

      The radius of the central circular area is  \frac{R}{2}

The discharging current is mathematically represented as

       I_d  =  \frac{A}{k} *  I

where A is the area of each plate which is mathematically represented as

       A  =  \pi R ^2

and   k is central circular area which is mathematically represented as

     k  =  \pi [\frac{R}{2} ]^2

So  

     I_d  =  \frac{\pi R^2 }{\pi * [ \frac{R}{2}]^2 } *  I

     I_d  =  \frac{\pi R^2 }{\pi *  \frac{R^2}{4} } *  I

     I_d  =  4 *  I

substituting values

     I_d  =  4 *  9.2

     I_d  =  36.8 \ A

     

7 0
3 years ago
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