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kipiarov [429]
3 years ago
15

21. Explique claramente como el fenotipo es el que favorece o desfavorece los resultados productivos obtenidos tanto en las expl

otaciones agrícolas como en las explotaciones pecuarias.
Engineering
1 answer:
Montano1993 [528]3 years ago
6 0
Los sistemas de producción pecuaria, son considerados como la estrategia social, económica y cultural más apropiada para mantener el bienestar de las comunidades, debido a que es la única actividad que puede simultáneamente proveer seguridad en el sustento diario, conservar ecosistemas, promover la conservación de la
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What is a core self-evaluation, include identifying and explaining the components of core self-evaluation. And, how a group lead
Brilliant_brown [7]

Answer and Explanation:

Core self-evaluations (CSEs) stands for a wide personality trait that comprises of 4 positive individual traits, namely:

(1) self-efficacy

(2) self esteem

(3) locus of control

(4) emotional stability.

Baiscally, when people have a positive evaluation about themselves, or quality core self-evaluation, they believe that they are worthy and fit for a task. They trust their capability and effectiveness. This leads to some implications in their managers duties and careers, which could either be positive or negative.

A group leader can use CSEs to create a more effective unit by implementing the ten items points of Generalized Self Efficacy Tool to test the self efficiency of individual personnels in that unit.

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3 years ago
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The engine of a 2000kg car has a power rating of 75kW. How long would it take (seconds) to accelerate from rest to 100 km/hr at
Delvig [45]

Answer: 10.29 sec.

Explanation:

Neglecting drag and friction, and at road level , the energy developed during the time the car is accelerating, is equal to the change in kinetic energy.

If the car starts from rest, this means the following:

ΔK = 1/2 m*vf ²

As Power (by definition) is equal to Energy/Time= 75000 W= 75000 N.m/seg, in order to get time in seconds, we need to convert 100 km/h to m/sec first:

100 (Km/h)*( 1000m /1 Km)*(3600 sec/1 h)= 27,78 m/sec

Now, we calculate the change in energy:

ΔK= 1/2*2000 Kg. (27,78)² m²/sec²= 771,728 J

<h2>If P= ΔK/Δt, </h2><h2>Δt= ΔK/P= 771,728 J / 75,000 J/sec= 10.29 sec.</h2>
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