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3 years ago

Dose mass alone determine wether an object floats or sink

1 answer:

5 0

As the mass increases, the object is more likely to... As the volume increases, the object is more likely to... If an object has a density less than that of water, it will float. If an object has a density more than that of water, it will sink.

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

Answer: The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

3 years ago

If it take 20 second for 200cm3 of H25 to diffuse through a porovs pot,hours,long will it take 400cm3 of NH3 of diffuse under th

trapecia [35]

Answer:

40 seconds chief just double it

Explanation:

5 0

3 years ago

Which of the following sentences describes oxygen at room temperature? (check all that apply)

Degger [83]

At room temperature, O2 is in gaseous state.

a gas has no definite volume or definite shape. It occupies volume of container and attains shape of container only.

Thus

It has no definite volume and takes the shape of its container.

Its particles move fast enough to overcome the attraction between them.: the gas molecules have minimum intermolecular interactions and have high kinetic energy.

It has more energy than it would at a cooler temperature: the kinetic energy of gas molecules increases with increase in temperature. Thus the energy increases with temperature and decreases with decrease in temperature.

5 0

3 years ago

Read 2 more answers

What volume will be occupied by 5.00 mol of a gas at 25°C and 0.500 atm pressure?"

fomenos

Answer:

The volume will be occupied is 244, 36L.

Explanation:

We convert the unit of temperature to celsius into Kelvin, then use the ideal gas formula, solve for V (volume) and use the gas constant R =0.082 l atm / K mol:

0°C=273K 25°C= 273 + 25=298K

PV=nRT ---> V=nRT/P

V= 5,00 mol x 0,082 l atm/ K mol x 298 K/0,500 atm

V=244,36L

4 0

3 years ago

If you had a glacier and an ice cube, how would the melting points of both differ?

Dima020 [189]

Answer:

Due to how big the glacier is you would need more heat to melt it and since the ice cube is smaller a small amount of heat would melt it

Explanation:

8 0

3 years ago