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SIZIF [17.4K]
2 years ago
14

How many electrons are needed for 1 coulomb of negative charge?​

Chemistry
1 answer:
Nadusha1986 [10]2 years ago
8 0

Answer:

Explanation:

A single electron has a charge of 1.60217733 × 10-19 Coulombs. A collection of 6.2415 × 1018 electrons has a charge of one Coulomb (1/1.60217733x10-19). 1.6 into 10 raise to power -19 no of electrons are present in one coulomb of charge.

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Answer:

18 Carats because of 75% Purity...

Explanation:

Red Gold Jewelry always contains a mixing of 25% copper by mass to make it durable and strong. That according to the simple parallel ratio rule, gives us a purity level of gold to be exactly 18 Carats. In other words the Red Gold is 75% pure...

4 0
3 years ago
When a 13.0g sample of NaOH(s) dissolves in 400.0 mL water in a coffee cup calorimeter, the temperature of the water changes fro
Tom [10]

Answer:440.154j

Explanation:

H=mcΔT

H= 13*4.18*8.1

H=440.154j

4 0
3 years ago
You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.
Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of <em>0,4mol / L</em>

100mL are <em>0,1L</em>. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = <em>7,01 g of indole-3-acetic acid</em>

<em></em>

Thus, <em>you need 7,01 g of indole-3-acetic acid to generate your solution</em>.

I hope it helps!

5 0
3 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
Leokris [45]

Answer:MnCO3+2H2O----->MnO2+ HCO3-+2e-+3H+

Explanation:The equation to be balanced is

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Therefore two electrons must be added to the right as shown below:

MnCO3 -------> MnO2+ HCO3-+ 2e-Now,there is one negative charge HCO3- and 1 negative charge on the two electrons making a total of -3 charges on the right. There is zero charge on the left.

To balance the equation,add3H+on the right,to cancel out the charges.

MnCO3 --------> MnO2+HCO3-+2e-+3H+

Adding H2O to balance Hydrogen and Oxygen atoms:

MnCO3+2H2O ------->MnO2+HCO3-+2e-+3H+

3 0
3 years ago
Electrons occupy certain high probability areas known as orbitals
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Not sure what you are asking but if it's a true or false question then the answer is true
5 0
3 years ago
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