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frez [133]
3 years ago
10

Which of the following statements is true?

Physics
1 answer:
inn [45]3 years ago
5 0
C is the right answe
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What is the difference in
andreev551 [17]

Answer:

0.438kg/ms-¹

Explanation:

Momentum, denoted by p, can be calculated by using the formula;

p = mv

Where;

m = mass (kg)

v = velocity (m/s)

Momentum (p) of bird = 0.216 kg × 5.87 m/s = 1.268kg/ms-¹

Momentum (p) of crawling baby = 7.29 kg kg × 0.234 m/s = 1.706kg/ms-¹

Having calculated the momentum of the bird to be 1.268kg/ms-¹, and the momentum of the baby to be 1.706kg/ms-¹, the difference in momentum between the flying bird and the crawling baby is:

{1.706kg/ms-¹ - 1.268kg/ms-¹} = 0.438kg/ms-¹

6 0
3 years ago
Read 2 more answers
a wire of a certain material has resistance r and diameter d a second wire of the same material and length is found to have resi
777dan777 [17]

Answer:

<h2>d₂ = 3d</h2><h2>The diameter of the second wire is 3 times that of the initial wire.</h2>

Explanation:

Using the formula for calculating the resistivity of an object to find the diameter.

Resistivity P = RA/L

R is the resistance of the material

A is the cross sectional area

L is the length of the material

Since A = πd²/4

P = R( πd²/4)/L

P = Rπd²/4L ... 1

If the second wire of the same material and length is found to have resistance R/9, the resistivity of the second material will be;

P₂ = (R/9)A₂/L₂

P₂ = (R/9)(πd₂²/4)/L₂

P₂ = (Rπd₂²/36)/L₂

P₂ = (Rπd₂²)/36L₂

Since the length and resistivity are the same;

P = P₂  and L =L₂

Equating 1 and 2;

Rπd²/4L =  (Rπd₂²)/36L₂

Rπd²/4L =  (Rπd₂²)/36L

d² = d₂²/9

d₂² = 9d²

Taking the square root of both sides;

√d₂² = √9d²

d₂ = 3d

Therefore the diameter of the second wire is 3 times that of the initial wire

5 0
3 years ago
An object is at rest in front of a compressed spring. It travels over a surface that exerts a kinetic frictional force on it and
PolarNik [594]

Answer:

the object will travel 0.66 meters before to stop.

Explanation:

Using the energy conservation theorem:

E_i+K_i+W_f=K_f+U_f

The work done by the friction force is given by:

W_f=F_f*d\\W_f=\µ*m*g*d\\W_f=0.35*4*9.81*d\\W_f=13.7d[J]

so:

\frac{1}{2}1800*(10*10^{-2})+0-13.7d=0+0\\d=0.66m

3 0
3 years ago
With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at
weeeeeb [17]

Answer:

F= 17,075\ N

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

F=m\cdot a

Where m is the mass of the car and a is the acceleration.

F=3,415\ kg\cdot 5\ m/s^2

\boxed{F= 17,075\ N}

3 0
3 years ago
What is a primary source?
Fed [463]
//////Correct answer is C.///////
6 0
3 years ago
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