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3 years ago

Which lengths can be used, directly or indirectly, to calculate the volume of the hexagonal right pyramid? Select three options.

Mathematics

2 answers:

grigory [225]3 years ago

6 0

Answer:

See below.

Step-by-step explanation:

The volume is 1/3 * height * area of the base so we need the height and this area to find the volume. Note: if we join the point S to each of the vertices of the base we get 6 equilateral triangles so knowing the length of a side of the base we can find the area of the base.

The following lengths can be used:

XY and ST We can get the area of the base knowing the length of XY and ST is the height.

VU and TW. From VU we can get the area of the base and the length of SW and from the length of TW and SW we can get the height.

TX and WX . From WX we can get the area of the base and the length of SX and from TX and SX we can find the height.

IrinaK [193]3 years ago

6 0

Answer:

A, B, D on edg

Step-by-step explanation:

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1/3 cup of flour is used to make 5 dinner rolls.

RoseWind [281]

we know that

$\frac{1}{3}$ cup of flour is used to make $5$ dinner rolls.

Part a) How much flour is needed to make one dinner roll?

by using proportion

$\frac{\frac{1}{3}}{5} =\frac{x}{1} \\ \\ x=\frac{\frac{1}{3}}{5}\\ \\ x=\frac{1}{15}$

therefore

the answer Part a) is

To make one dinner roll is needed $\frac{1}{15}$ cup of flour

Part b) How many cups of flour are needed to make 3 dozen dinner rolls?

Multiply the value obtained in part a) by $36$

$\frac{1}{15} *36=\frac{36}{15} \\ \\ =\frac{12}{5}$

$\frac{12}{5} =2\frac{2}{5}$

therefore

the answer Part b) is

To make $3$ dozen dinner rolls are needed $2\frac{2}{5}$ cup of flour

Part c) How many rolls can you make with 5 2/3 cups of flour?

$5\frac{2}{3} =\frac{17}{3}$

by using proportion

$\frac{\frac{1}{3}}{5} =\frac{\frac{17}{3}}{x} \\ \\ \frac{x}{3} =\frac{85}{3} \\ \\ x=85$

therefore

the answer part c) is

$85$ rolls

6 0

3 years ago

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What is the slope of the line that includes points (36,-30) and (39,27)

DedPeter [7]

Answer:

The slope of the line is 19

Step-by-step explanation:

slope=(y2-y1)/(x2-x1)=(27-(-30))/(39-36)=57/3=19

Therefore, the slope of the line is 19

7 0

2 years ago

Given s = 10 and h = 15. Find the total surface area of the square prism.

anastassius [24]

Answer:

150

Step-by-step explanation:

h = hight

s = sides

surface = 10 x 15

surface = 150

(V = 10 x 10 x 15

(V = 100 x 15)

(V = 1500)

(Base area = B)

(B = Lenght x Width)

(B = 10 x 10)

(B = 100)

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2 years ago

Of 575 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of ba

chubhunter [2.5K]

Answer:

a) $0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

b) We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

c) For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p =0.68$ represent the estimated proportion

n=575 is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

Part b

We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

Part c

For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

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3 years ago

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