Answer:
a) a = 19.0 m/s²
b) a = 2.9 m/s²
Explanation:
a) We draw the free body diagram of the box. There are 4 forces: the normal force N, the weight mg, the constant force F and the kinetic frictional force μ_kN. We can take the coordinate system which is rotated 55° from the horizontal, to ease the calculations. So, we write the equations of motion in each axis:
Substituting the expression for N in the first equation, we have:
If we plug in the given values, we have:
Since we chose the right-downward direction as positive, the positive sign in this case means that the box is accelerated downwards above the ramp.
b) In this case, the constant force F and the kinetic frictional force μ_kN point to the opposite side. In other words, we can just only change the sign of this two forces in the equations of part (a) and obtain:
Plugging in the given values:
Since we chose the right-downward direction as positive, the negative sign in this case means that the box is accelerated upwards above the ramp.
This means that the magnitude of the acceleration in this case is 2.9m/s².