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Nesterboy [21]
3 years ago
8

How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air

Physics
1 answer:
Tcecarenko [31]3 years ago
5 0

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

y = -(1/2)(9.8 m/s^2)(3 s)^2 + (40 m/s)(3 s)

= -44.1 m + 120 m

= 75.9

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The 26-kg sphere c is released from rest when θ = 0∘ and the tension in the spring is f = 100 n
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You are given the mass of a sphere that is 26 kg sphere and it is released from rest when θ = 0°. You are also given the force of the spring that is F = 100 N. You are asked to find the tension of the spring. Imagine that the sphere is connected to a spring. The spring exerts a tension and the spring exerts gravitational pull. This will follow the second law of newton.

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